如何在没有后端的情况下发送角度6表格？

Question

我正在尝试创建一个角度为6的网站，并通过联系表格发送电子邮件。

该网站部署在apache服务器上，没有后端，只有Angular 6 html和javascript文件。

我的电子邮件地址上有maillet / mailgun帐户，firebase帐户和smtp访问权限。

是否可以仅发送角度为6的电子邮件？ 我怎样才能做到这一点？

谢谢。 :)

Answer 1

您不能仅使用Angular来做到这一点，这是一个使用Angular和少量PHP发送电子邮件的示例：

HTML形式：

<form [formGroup]="subscribeForm" novalidate (ngSubmit)="sendMail($event)">
    <input type="text" placeholder="Enter your email" formControlName="email"/>
    <button class="button margin-top-15" type="submit">Subscribe</button>
</form>

ts文件：

export class MyComponent implements OnInit, OnDestroy {

    public subscribeForm: FormGroup;
    public email: FormControl;
    private unsubscribe = new Subject<void>();

    constructor(private databaseService: DatabaseService, private mailerService: MailerService, private http: HttpClient) { }

    ngOnInit() {
        this.createFormControls();
        this.createForm();
    }

    createFormControls() {
        this.email = new FormControl('', [
            Validators.required
        ]);
    }

    createForm() {
        this.subscribeForm = new FormGroup({
            email: this.email
        });
    }

    sendMail() {
        if (this.subscribeForm.valid) {
            this.http.post("link to the php file.", email).subscribe();
        }
    }

    ngOnDestroy(): void {
        this.unsubscribe.next();
        this.unsubscribe.complete();
    }

}

并在php文件中：

<?php
    header('Content-type: application/json');
    header("Access-Control-Allow-Origin: *");
    header("Access-Control-Allow-Headers: Origin, X-Requested-With, Content-Type, Accept");
    $request = json_decode(file_get_contents("php://input"));
    $from_email = "your email goes here";

    $message = "Welcome.";

    $from_name = "your name goes here";

    $to_email = $request->email;

    $contact = "<p><strong>Name:</strong>$from_name</p><p><strong>Email:</strong> $from_email</p>";

    $email_subject = "Angular Php Email Example: Neue Nachricht von $from_name erhalten";

    $email_body = '<html><body>';
    $email_body .= "$<p><strong>Name:</strong>$from_name</p><p><strong>Email:</strong> $from_email</p>
                    <p>$message</p>";
    $email_body .= '</body></html>';

    $headers .= "MIME-Version: 1.0\r\n";
    $headers .= "Content-Type: text/html; charset=ISO-8859-1\r\n";
    $headers .= "From: $from_email\n";
    $headers .= "Reply-To: $from_email";

    mail($to_email,$email_subject,$email_body,$headers);

    $response_array['status'] = 'success';
    $response_array['from'] = $from_email;

    echo json_encode($response_array);
    echo json_encode($from_email);
    header($response_array);
    return $from_email;
?>

如何在没有后端的情况下发送角度6表格？

问题描述

1 个解决方案

解决方案1
2 已采纳 2018-08-24 17:55:45

如何在没有后端的情况下发送角度6表格？

问题描述

1 个解决方案

解决方案1 2 已采纳 2018-08-24 17:55:45

解决方案1
2 已采纳 2018-08-24 17:55:45