使用Spring Boot在angular 6中上传文件或上传图像

Question

请帮我或建议我

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有什么可能的方式使用formcontrolName在表单中上传图像，请提出一些建议

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我正在尝试上传带有其他信息的图像文件，例如firstname ， lastname和file ，这很完美：

/* File Upload request  to Upload file  */
this.currentFileUpload = this.selectedFiles.item(0);
let formdata: FormData = new FormData();
formdata.append('firstName', "Harkesh");
formdata.append('lastName', "kumar");
formdata.append('file', this.currentFileUpload);

但是我的问题是我正在发送带有一些字符串和Object FORM文件，但是FormData不接受Object ：

let formdata: FormData = new FormData();
formdata.append('functionId', this.functionId);
formdata.append('processId', this.processId);
formdata.append('file', this.currentFileUpload);
formdata.append('formDetails', userobjArr);

我正在尝试的第二个选择：

let formdata: FormData = new FormData();
formdata.append('file', this.currentFileUpload);

userDetails.name = "";
userobjWrapper["functionId"] = this.functionId;
userobjWrapper["processId"] = this.processId;
userobjWrapper["taskId"] = this.taskId;
userobjWrapper["file"] = this.currentFileUpload;
userobjWrapper["formDetails"] = userobjArr;

userobjArr是我用formDetails分配的Object数组，它正在获取null值。

我不确定如何在一次其余的Service API调用中读取图像？ 对于REST API，我正在使用Spring Boot Rest Controller

你能建议我任何想法吗..

Answer 1

试试这个:)

onBmpFileUploadChange(event) {
    const self = this;
    const target = event.target || event.srcElement;
    const files = target.files;
    let arrPath = files[0].name;
    arrPath = arrPath.split('.');
    if ((arrPath[1] === 'bmp') || (arrPath[1] === 'BMP')) {
      const xhttp = new XMLHttpRequest();
      const formData = new FormData();
      console.log('uploadBitmap');
      formData.append('bitmapFile', files[0]);
      xhttp.onreadystatechange = function () {
        event.target.value = null;
        if (this.readyState === 4) {
          if (this.status === 201) {
            console.log('bmpUploadedSuccessfully');
          } else {
            console.log('bmpUploadFailed')));
          }
        }
      };
      xhttp.open('post', '/formatgraphics', true);
      xhttp.setRequestHeader('Pragma', 'no-cache');
      xhttp.send(formData);
    } else {
      console.log('uploadFailedInvalidFile')));
    }
  }
}