[英]SQL Exclude Records with multiple values based on values from a different column
在SQL中,我有一个ID列表以及与其关联的REC号。 我的目标是删除具有0 RECNO的行,但前提是只有另一行具有非0 RECNO的行。
之前:
DLREC# RECNO
3583 | 0
586 | 0
3589 | 0
3589 | 123456789
3609 | 0
3650 | 0
3650 | 451230149
后:
DLREC# RECNO
3583 | 0
3586 | 0
3589 | 123456789
3609 | 0
3650 | 451230149
使用样本数据的简单方法是MAX
select
[DLREC#]
,max(RECNO)
from YourTable
group by [DLREC#]
对于SQL Server
如果每个DLREC#
值都更多,则另一种方法是窗口函数
with cte as(
select *
,RN = row_number() over (partition by [DLREC#] order by RECNO)
,CT = count(*) over (partition by [DLREC#]))
select
[DLREC#]
,RECNO
from CTE
where (RN != 1 and CT > 1) or (RN = 1 and CT = 1)
您可以将not exists
与delete
:
delete t from t
where recno = 0 and
exists (select 1 from t t2 where t2.dlrec = t.dlrec and t2.recno <> 0);
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