[英]Get Last Value from Previous Window Partition in Teradata SQL
[英]Hive window functions: last value of previous partition
使用Hive窗口函数,我想获取上一个分区的最后一个值:
| name | rank | type |
| one | 1 | T1 |
| two | 2 | T2 |
| thr | 3 | T2 |
| fou | 4 | T1 |
| fiv | 5 | T2 |
| six | 6 | T2 |
| sev | 7 | T2 |
以下查询:
SELECT
name,
rank,
first_value(rank over(partition by type order by rank)) as new_rank
FROM my_table
将给出:
| name | rank | type | new_rank |
| one | 1 | T1 | 1 |
| two | 2 | T2 | 2 |
| thr | 3 | T2 | 2 |
| fou | 4 | T1 | 4 |
| fiv | 5 | T2 | 5 |
| six | 6 | T2 | 5 |
| sev | 7 | T2 | 5 |
但是我需要的是“上一个分区的最后一个值”:
| name | rank | type | new_rank |
| one | 1 | T1 | NULL |
| two | 2 | T2 | 1 |
| thr | 3 | T2 | 1 |
| fou | 4 | T1 | 3 |
| fiv | 5 | T2 | 4 |
| six | 6 | T2 | 4 |
| sev | 7 | T2 | 4 |
这似乎很棘手。 这是“群岛”的一种变体。 这是想法:
lag()
将先前的等级引入该岛。 所以:
with gi as (
select t.*,
(seqnum - seqnum_t) as grp
from (select t.*,
row_number() over (partition by type order by rank) as seqnum_t,
row_number() over (order by rank) as seqnum
from t
) t
),
gi2 as (
select gi.*, lag(rank) over (order by gi.rank) as prev_rank
from gi
)
select gi2.*,
min(prev_rank) over (partition by type, grp) as new_rank
from gi2
order by rank;
这是一个SQL Fiddle(尽管使用Postgres)。
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