比较两个数组对象数据并在JavaScript中将一个对象合并为一个数组？

Question

我的数组：

const create = [{"month":"Jan","createCount":"4"},{"month":"Feb","createCount":"5"}];

const close = [{"month":"Jan","closeCount":"3"},{"month":"Feb","closeCount":"5"}];

我需要合并数组对象以比较月份字段。

我想要这样的结果 ...

const data = [{"month":"Jan","createCount":"4","closeCount":"3"},{"month":"Feb","createCount":"5","closeCount":"5"}];

我尝试了这段代码：

const data = [...create, ...close];

但这仅是合并两个数组数据。

请给我任何解决方案！

Answer 1

您可以使用.map()和Object.assign()方法：

 const create = [{"month":"Jan","createCount":"4"}, {"month":"Feb","createCount":"5"}], close = [{"month":"Jan","closeCount":"3"}, {"month":"Feb","closeCount":"5"}]; const result = create.map( o => Object.assign({}, o, close.find(({month}) => month === o.month)) ); console.log(result); 

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Answer 2

假设在create数组中没有在close数组中不存在的条目，反之亦然

尝试使用Array.reduce ， Array.map和Object.assign进行以下操作

 const create = [{"month":"Jan","createCount":"4"},{"month":"Feb","createCount":"5"}]; const close = [{"month":"Jan","closeCount":"3"},{"month":"Feb","closeCount":"5"}]; // Create an object with key as month and createCount as value let obj = create.reduce((a, o) => Object.assign(a, {[o.month]: o.createCount}), {}); // Iterate over close array and add createCount from obj let result = close.map(o => ({...o, createCount : obj[o.month]})); console.log(result); 

Answer 3

简单地用于

const create = [{ "month": "Jan", "createCount": "4" }, { "month": "Feb", "createCount": "5" }];
const close = [{ "month": "Jan", "closeCount": "3" }, { "month": "Feb", "closeCount": "5" }];
for (var i in create) {
    var item = create[i];
    item.closeCount = close.find(x => x.month == item.month).closeCount;
}
console.log(create);

Answer 4

在这里我添加了一些示例，请参考该代码

 const create = [{"month":"Jan","createCount":"4"},{"month":"Feb","createCount":"5"}]; const close = [{"month":"Jan","closeCount":"3"},{"month":"Feb","closeCount":"5"}]; console.log(create.length); for(var data = 0 ; data < create.length ; data++){ var datas = [] if(create[data].month == close[data].month){ datas=Object.assign(create[data],close[data]);console.log(create[data]); } }