仅当警报显示在Browser Selenium java中时，如何单击该警报？

Question

这是测试方案

• 步骤1：-输入用户名和密码
• 第2步：-如果用户已经登录， 将显示一个警报/弹出窗口，并带有注销链接，然后单击该链接以退出并尝试再次登录。

这是该警报的HTML代码

<div class="top-alert hidden-xs hidden-sm">
    <div id="alert0" class="alert pull-right alert-danger alert-dismissable" style="display:none;">
        <button type="button" class="close" data-dismiss="alert" aria-hidden="true">&times;</button>
        <strong>Error:</strong> Invalid Inputs!
    </div>
    <div id="alert2" class="alert pull-right alert-warning alert-dismissable" style="display:none;">
        <button type="button" class="close" data-dismiss="alert" aria-hidden="true">&times;</button>
        <strong>Warning:</strong> Your Login is limited
    </div>
    <div id="alert3" class="alert pull-right alert-warning alert-dismissable" style="display:none;">
        <button type="button" class="close" data-dismiss="alert" aria-hidden="true">&times;</button>
        <strong>Warning:</strong> You are Already Loggedin <a href="http://localhost/myapp/public/logout">Logout</a>
    </div>
</div>

这是网站截图

这是我的解决方案

public class Test
{
    public static void main(String[] args)
    {
        System.setProperty("webdriver.chrome.driver", "C:\\\\Selenium\\\\drivers\\\\chromedriver.exe");
        WebDriver driver = new ChromeDriver();
        driver.get("http://localhost/myapp/public/login");

        // Maxmimize windows
        driver.manage().window().maximize();

        // Login the Tripmaker
        driver.findElement(By.xpath("//input[@id='email']")).sendKeys("test@test.com");
        driver.findElement(By.id("password")).sendKeys("s123456");
        driver.findElement(By.cssSelector("#lsbt")).click();

        // Explicit wait
        if (!driver.findElement(By.xpath("//div[@class='top-alert hidden-xs hidden-sm']/div[@id='alert3']/a[contains(text(), 'Logout')]")).isDisplayed())
        {
            WebDriverWait alert = new WebDriverWait(driver, 5);
            alert.until(ExpectedConditions.visibilityOfElementLocated(By.xpath("//div[@class='top-alert hidden-xs hidden-sm']/div[@id='alert3']/a[contains(text(), 'Logout')]")));
            driver.findElement(By.xpath("//div[@class='top-alert hidden-xs hidden-sm']/div[@id='alert3']/a[contains(text(), 'Logout')]")).click();
        }
        else if (driver.findElement(By.xpath("//div[@class='top-alert hidden-xs hidden-sm']/div[@id='alert3']/a[contains(text(), 'Logout')]")).isDisplayed()) 
        {           
            System.out.println("This step is skipped");
        }
    }
}

我的代码正常工作，但如果登录时显示警告，则抛出错误

Exception in thread "main" org.openqa.selenium.TimeoutException: Expected condition failed: waiting for visibility of element located by By.xpath: //div[@class='top-alert hidden-xs hidden-sm']/div[@id='alert3']/a[contains(text(), 'Logout')] (tried for 5 second(s) with 500 milliseconds interval)
  at org.openqa.selenium.support.ui.WebDriverWait.timeoutException(WebDriverWait.java:113)
  at org.openqa.selenium.support.ui.FluentWait.until(FluentWait.java:283)
  at demo.myapp.main(myapp.java:41)
Caused by: org.openqa.selenium.NoSuchElementException: Cannot locate an element using By.xpath: //div[@class='top-alert hidden-xs hidden-sm']/div[@id='alert3']/a[contains(text(), 'Logout')]

我尝试了.isDisplayed() .isSelected()和.isEnabled () 。

Answer 1

您可以像这样通过try-catch块处理弹出窗口，

try {
      if(driver.findElement(By.id("alert3")).isDisplayed())
      {
      driver.findElement(By.linkText("Logout")).click();
      }
} catch(Exception e) {
      System.out.println("User defined Message");
}

Answer 2

根据您的用例 ，等待带有退出链接的警报出现，然后单击带有文本的链接作为退出，您需要诱导WebDriverWait使元素可单击，并且可以使用以下代码块：

//Login the Tripmaker
driver.findElement(By.xpath("//input[@id='email']")).sendKeys("test@test.com");
driver.findElement(By.id("password")).sendKeys("s123456");
driver.findElement(By.cssSelector("#lsbt")).click();
try {
    new WebDriverWait(driver, 20).until(ExpectedConditions.elementToBeClickable(By.xpath("//div[@class='top-alert hidden-xs hidden-sm']//div[@class='alert pull-right alert-warning alert-dismissable' and @id='alert3']//a[@href='http://localhost/myapp/public/logout']"))).click();
}
catch (TimeoutException e) { 
    System.out.println("Element is not present");
}

Answer 3

我在您的代码中修复了一些问题。 您混合使用了By.id() ， By.cssSelector()和By.XPath()查找所有具有ID的元素。 只要有ID并使用By.id()您就应该首选ID。 if不必要的if ，您还有很多额外的东西。 您检查了该元素是否不可见，然后等待它可见，然后再次找到它并单击它，否则，如果它不可见，则打印一条消息。 总而言之，您只需要执行一次就可以找到该元素4次。

由于该元素可能存在或可能不存在，并且我们需要等待它，因此您需要在try-catch等待中加上try-catch 。

public class Test
{
    public static void main(String[] args)
    {
        System.setProperty("webdriver.chrome.driver", "C:\\\\Selenium\\\\drivers\\\\chromedriver.exe");
        WebDriver driver = new ChromeDriver();
        driver.get("http://localhost/myapp/public/login");

        // Maxmimize windows
        driver.manage().window().maximize();

        // Login the Tripmaker
        driver.findElement(By.id("email")).sendKeys("test@test.com");
        driver.findElement(By.id("password")).sendKeys("s123456");
        driver.findElement(By.id("lsbt")).click();

        try
        {
            // wait for the logout link in the dialog and click it
            new WebDriverWait(driver, 3).until(ExpectedConditions.elementToBeClickable(By.cssSelector("#alert3 a[href$='logout']"))).click();
        }
        catch (TimeoutException)
        {
            // logout link was never displayed
            System.out.println("This step is skipped");
        }
    }
}