[英]CASE on two rows with identical IDs but different values
一种选择使用EXISTS
:
SELECT DISTINCT ID
FROM yourTable t1
WHERE NOT EXISTS (SELECT 1 FROM yourTable t2 WHERE t1.ID = t2.ID AND t2.Result <> t1.Result);
另一个选项使用聚合:
SELECT ID
FROM yourTable
GROUP BY ID
HAVING COUNT(DISTINCT Result) = 1;
如果您想要每个 id 一行,请使用group by
:
select id,
(case when min(result) = max(result) then 'Passed'
else 'Failed'
end) as flag
from t
group by id;
如果您想要原始表的所有行上的值,那么很简单:
select id,
(case when not exists (select 1
from t t2
where t2.result) = t.result
)
then 'Passed' else 'Failed'
end) as flag
from t
group by id;
然而,并将结果在一行上是有问题的。 无法区分行,因此更具挑战性(并非不可能,但我怀疑上述方法之一可以解决您的真正问题)。
试试下面:
select id, case when count (distinct result)=1 then 'Passed' else 'Failed' end
group by id
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