[英]Select a column from subquery inside select?
如何从子查询到父查询中选择Attr1? 我试图使用Average.Attr1,但不起作用。
不是单组分组功能
SELECT SUM(Report.Attr1),
SUM(Report.Attr2),
SUM(Report.Attr3),
0
FROM {Report},
(
SELECT AVG(Report.Attr1),
AVG(Report.Attr2),
AVG(Report.Attr3)
FROM Report
WHERE
StartDate <= Report.Date AND
Report.Date <= EndDate
GROUP BY Report.Attr1, Report.Attr2, Report.Attr3
) Average
WHERE
StartDate <= Report.Date AND
Report.Date <= EndDate
您可以为这些聚合函数添加别名,以便可以在外部查询中使用它们
SELECT SUM(avg_attr1),
SUM(avg_attr2),
SUM(avg_attr3),
0
FROM {Report},
(
SELECT AVG(Report.Attr1) as avg_attr1,
AVG(Report.Attr2) as avg_attr2,
AVG(Report.Attr3) as avg_attr3
...
或者,如果您只想限制它们,则可以将HAVING子句与GROUP BY一起使用
...
GROUP BY Report.Attr1, Report.Attr2, Report.Attr3
HAVING AVG(Report.Attr1) > {SomeNumber}
) Average
...
我不确定这是否是您想要的,但是我可以通过以下方法使它起作用:
WITH REPORT (STARTDATE,ENDDATE,DATE1,ATTR1,ATTR2,ATTR3)AS(
SELECT DATE '2018-01-01',DATE '2018-02-01',DATE '2018-01-11', 1,2,3 FROM DUAL UNION ALL
SELECT DATE '2018-01-01',DATE '2018-02-01',DATE '2018-01-11',1,2,3 FROM DUAL UNION ALL
select date '2018-01-01',DATE '2018-02-01',DATE '2018-01-11',1,2,3 from dual
)
SELECT SUM(Report.Attr1),
SUM(Report.Attr2),
SUM(REPORT.ATTR3),
0,
average.a,average.b,average.c
FROM REPORT,
(
SELECT AVG(REPORT.ATTR1) A,
AVG(REPORT.ATTR2) B ,
AVG(Report.Attr3) c
FROM Report
WHERE
STARTDATE <= REPORT.DATE1 AND
Report.Date1 <= EndDate
GROUP BY Report.Attr1, Report.Attr2, Report.Attr3
) Average
WHERE
STARTDATE <= REPORT.DATE1 AND
REPORT.DATE1 <= ENDDATE
GROUP BY 0,
average.a,average.b,average.c
您可以通过提供别名来引用它们。 现在,如果您说“ Average.attr
您将获得与Report.Attr1
相对应的值
SELECT SUM(Report.Attr1),
SUM(Report.Attr2),
SUM(Report.Attr3),
0,
Average.attr
FROM {Report},
(
SELECT AVG(Report.Attr1) as attr,
AVG(Report.Attr2),
AVG(Report.Attr3)
FROM Report
WHERE
StartDate <= Report.Date AND
Report.Date <= EndDate
GROUP BY Report.Attr1, Report.Attr2, Report.Attr3
) Average
WHERE
StartDate <= Report.Date AND
Report.Date <= EndDate
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