没有在PHP中获取正确的JSON数据

Question

$events = array();
$employeeData = array();
foreach ($rows as $fetch)
{ 
    $employeeData['start_date'] = $fetch->start_date;
    $employeeData['events']['start_time'] = $fetch->start_time;
    $employeeData['events']['end_time'] = $fetch->end_time;

    $employeeData['events']['name'] = $fetch->FirstName. ' ' .$fetch->LastName;

   array_push($events, $employeeData);
}

$success_status = array(
    'events'=> $events
);

echo json_encode($success_status, true);

结果 - - - - - -

{“ events”：[{“ start_date”：“ 2018-05-27”，“ events”：{“ start_time”：“ 11:45:00”，“ end_time”：“ 13:00:00”，“名称“：” Demo“}}，{” start_date“：” 2018-06-29“，” events“：{” start_time“：” 15:30:00“，” end_time“：” 15:45:00“， “ name”：“ Demo”}}，{“ start_date”：“ 2018-06-29”，“ events”：{“ start_time”：“ 16:30:00”，“ end_time”：“ 23:45:00 “，” name“：” Demo“}}]}

我得到上述结果，但我需要得到以下结果

{“ events :: [{” start_date“：” 2018-05-27“，” events“：[{” start_time“：” 11:45:00“，” end_time“：” 13:00:00“，” name“：” Demo“}]}，{” start_date“：” 2018-06-29“，” events“：[{” start_time“：” 15:30:00“，” end_time“：” 15:45： 00“，” name“：” Demo“}，{” start_time“：” 16:30:00“，” end_time“：” 23:45:00“，” name“：” Demo“}]}]}

Answer 1

我认为这应该在以后产生输出，这是在要嵌套在[{...}]的数据上添加额外的数组层的情况。

$employeeData['events'][] = ['start_time' => $fetch->start_time, 
                             'end_time' =>$fetch->end_time,
                             'name' => $fetch->FirstName. ' ' .$fetch->LastName ];

因此，这使用[]仅将数据添加到一个数组中，而我将元素包装到一个数组中，而不是将其添加为项目。

Answer 2

$employeeData['events']['start_time']基本上是将单个项目创建为关联数组。 您想要的是一系列事件项。 因此，您需要将事件数据放入数组中，然后将该数组添加到events数组中，如下所示：

$events = array();
$employeeData = array();
foreach ($rows as $fetch)
{ 
    $event = [];
    $employeeData['start_date'] = $fetch->start_date;
    $event['start_time'] = $fetch->start_time;
    $event['end_time'] = $fetch->end_time;

    $event['name'] = $fetch->FirstName. ' ' .$fetch->LastName;
    $employeeData['events'][] = $event;

   array_push($events, $employeeData);
}

$success_status = array(
    'events'=> $events
);

echo json_encode($success_status, true);