![](/img/trans.png)
[英]PostgreSQL update JSONB column from JSON string to Array of JSON objects
[英]Search by date in array of objects within PostgreSQL JSONB Column
我的 PostgreSQL 9.6 实例中有两个表。
users
+----+------------+-----------+-------------------+
| id | first_name | last_name | email |
+----+------------+-----------+-------------------+
| 1 | John | Doe | john.doe@test.com |
+----+------------+-----------+-------------------+
| 2 | Jane | Doe | jane.doe@test.com |
+----+------------+-----------+-------------------+
| 3 | Mike | Doe | mike.doe@test.com |
+----+------------+-----------+-------------------+
surveys
+----+---------+----------------------------------------------------------------------------------------------------+
| id | user_id | survey_data |
+----+---------+----------------------------------------------------------------------------------------------------+
| 1 | 1 | {'child_list': [{'gender': 1, 'birthday': '2015-10-01'}, {'gender': 2, 'birthday': '2017-05-01'}]} |
+----+---------+----------------------------------------------------------------------------------------------------+
| 2 | 2 | {'child_list': []} |
+----+---------+----------------------------------------------------------------------------------------------------+
| 3 | 3 | {'child_list': [{'gender': 2, 'birthday': '2008-01-01'}]} |
+----+---------+----------------------------------------------------------------------------------------------------+
我希望能够查询这两个表以获取在特定年龄之间有孩子的用户数量。 该survey_data
列surveys
表是JSONB列。
到目前为止,我已经尝试将jsonb_populate_recordset
与LATERAL
连接一起使用。 我能够将child_list
数组SELECT
为两列,但无法弄清楚如何在users
和surveys
表之间使用我的JOIN
。 我使用的查询如下:
SELECT DISTINCT u.email
FROM surveys
CROSS JOIN LATERAL (
SELECT *
FROM jsonb_populate_recordset(null::json_type, (survey.survey_data->>'child_list')::jsonb) AS d
) d
INNER JOIN users u ON u.id = survey.user_id
WHERE d.birthday BETWEEN '2014-05-05' AND '2018-05-05';
这也使用了使用此创建的自定义类型:
CREATE type json_type AS (gender int, birthday date)
我的问题是,有没有更容易阅读的方法来做到这一点? 我想将此查询与许多其他JOIN
和WHERE
子句一起使用,我想知道是否有更好的方法来做到这一点。
注意:这主要由不需要超快但当然欢迎任何速度提升的报告系统使用。
使用函数jsonb_array_elements(),
示例:
select email, (elem->>'gender')::int as gender, (elem->>'birthday')::date as birthday
from users u
left join surveys s on s.user_id = u.id
cross join jsonb_array_elements(survey_data->'child_list') as arr(elem)
email | gender | birthday
-------------------+--------+------------
john.doe@test.com | 1 | 2015-10-01
john.doe@test.com | 2 | 2017-05-01
mike.doe@test.com | 2 | 2008-01-01
(3 rows)
或者
select distinct email
from users u
left join surveys s on s.user_id = u.id
cross join jsonb_array_elements(survey_data->'child_list') as arr(elem)
where (elem->>'birthday')::date between '2014-05-05' and '2018-05-05';
email
-------------------
john.doe@test.com
(1 row)
您可以使用视图让您的生活更轻松:
create view users_children as
select email, (elem->>'gender')::int as gender, (elem->>'birthday')::date as birthday
from users u
left join surveys s on s.user_id = u.id
cross join jsonb_array_elements(survey_data->'child_list') as arr(elem);
select distinct email
from users_children
where birthday between '2014-05-05' and '2018-05-05';
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.