[英]only select records that repear mysql
我有以下查询
SELECT id
, created_date
, longitude
, latitude
FROM score s
where s.mobile_user_id = 14299
and latitude != 0
and created_date > '2018-10-01 12:00:00'
and speed_range_id > 1
group
by latitude, longitude
order
by id asc;
这将返回以下结果:
ID CREATED_DATE LAT LON
8289173 2018-10-02 16:52:54 -100.40871983 20.56314546
8991287 2018-10-07 18:06:37 -100.40879701 20.56899227
9077533 2018-10-08 11:55:31 -100.39687493 20.57479211
9077534 2018-10-08 11:55:31 -100.36075875 20.58076244
9077535 2018-10-08 11:55:31 -100.37852743 20.60783806
9077536 2018-10-08 11:55:31 -100.36473954 20.61464554
9077537 2018-10-08 11:55:31 -100.36424849 20.61501740
9077538 2018-10-08 11:55:31 -100.40951731 20.60529101
9227761 2018-10-09 18:10:00 -100.40851908 20.61148848
9227762 2018-10-09 18:10:00 -100.40545509 20.61769963
9227763 2018-10-09 18:10:00 -100.38008197 20.61098901
9227764 2018-10-09 18:10:00 -100.36462022 20.61464574
9227765 2018-10-09 18:10:00 -100.34415272 20.61327334
9227766 2018-10-09 18:10:00 -100.33583425 20.61397514
但是,我只想选择多个具有相同created_date的记录,例如本示例中的日期2018-10-08 11:55:31和2018-10-09 18:10:00。 我如何编写查询以忽略不重复的前2个?
我尝试通过使用created_date> 1来尝试,但它似乎不起作用。
有任何想法吗?
由于LAT&LON有所不同,因此无法正常工作,因为您的小组在LAT&LON上。
尝试这个 :
SELECT id, created_date ,longitude,latitude
FROM napify.score s
where s.mobile_user_id = '14299' and latitude != 0.00000000 and created_date > '2018-10-01 12:00:00' and speed_range_id > 1
and created_date in (select created_date from napify.score group by created_date having count(*) > 1)
group by latitude, longitude
order by id asc;
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