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[英]Java database abstraction for GWT (or: Is Hibernate a good choice?)
[英]Hibernate entities abstraction
我有两个班级Team和User:
@Entity
@Table(name = "team")
@Cache(usage = CacheConcurrencyStrategy.NONSTRICT_READ_WRITE)
public class Team extends AbstractAuditingEntity implements Serializable, Participant {
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "sequenceGenerator")
@SequenceGenerator(name = "sequenceGenerator")
private Long id;
和
@Entity
@Table(name = "user")
@Cache(usage = CacheConcurrencyStrategy.NONSTRICT_READ_WRITE)
@org.springframework.data.elasticsearch.annotations.Document(indexName = "user")
public class User extends AbstractAuditingEntity implements Serializable, Participant {
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "sequenceGenerator")
@SequenceGenerator(name = "sequenceGenerator")
private Long id;
我想创建新的实体匹配。 比赛可以有2位参与者。 参与者可以是团队或用户。 我想创建抽象,以便我可以添加团队或用户以匹配参与者。 我想创建接口参与者并使用@MappedSuperclass进行映射,然后使用团队和用户来实现参与者,但是我遇到了错误:
org.hibernate.AnnotationException:Match.participant上的@OneToOne或@ManyToOne首先引用了一个未知实体:Participant
@MappedSuperclass
public interface Participant {
}
有用的链接: 具有休眠注释的接口和http://docs.jboss.org/hibernate/core/3.3/reference/en/html/inheritance.html#inheritance-tableperconcrete
根据文档,使用XML映射可能会有所帮助,
If your superclass is abstract, map it with abstract="true". If it is not abstract, an additional table (it defaults to PAYMENT in the example above), is needed to hold instances of the superclass.
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