Dynamics CRM QueryExpression 嵌套的 LinkedEntity

Question

我正在尝试从Contact实体中检索数据，将其加入Function实体，然后将Function加入Account实体。

这个想法是使用单个查询来检索联系人数据以及其他两个中的一些额外字段。

我能够从Function链接实体加入和检索数据，但我无法理解如何使用嵌套链接实体。

QueryExpression queryExpression = new QueryExpression(Contact.EntityLogicalName);

queryExpression.ColumnSet = new ColumnSet(Contact.Fields.pix_GZGId, Contact.Fields.Id, Contact.Fields.FirstName, Contact.Fields.LastName, 
    Contact.Fields.MiddleName, Contact.Fields.GenderCode, Contact.Fields.EMailAddress1, Contact.Fields.EMailAddress2, 
    Contact.Fields.Telephone2, Contact.Fields.MobilePhone, Contact.Fields.pix_Gastlessenoptin);
FilterExpression emailFilter = new FilterExpression(LogicalOperator.Or);

emailFilter.AddCondition(Contact.Fields.EMailAddress1, ConditionOperator.Equal, email);
emailFilter.AddCondition(Contact.Fields.EMailAddress2, ConditionOperator.Equal, email);

FilterExpression nameFilterAll = new FilterExpression(LogicalOperator.And);
nameFilterAll.AddCondition(Contact.Fields.FirstName, ConditionOperator.Equal, firstname);
nameFilterAll.AddCondition(Contact.Fields.LastName, ConditionOperator.Equal, lastname);

if (!String.IsNullOrEmpty(middlename))
{
    nameFilterAll.AddCondition(Contact.Fields.MiddleName, ConditionOperator.Equal, middlename);
}

FilterExpression nameFilterPartial = new FilterExpression(LogicalOperator.And);
nameFilterPartial.AddCondition(Contact.Fields.FirstName, ConditionOperator.BeginsWith, firstname.Substring(0,1));
nameFilterPartial.AddCondition(Contact.Fields.LastName, ConditionOperator.Equal, lastname);

FilterExpression nameFilterLast = new FilterExpression();
nameFilterLast.AddCondition(Contact.Fields.LastName, ConditionOperator.Equal, lastname);

FilterExpression completeNameFilter = new FilterExpression(LogicalOperator.Or);
completeNameFilter.Filters.Add(nameFilterAll);
completeNameFilter.Filters.Add(nameFilterPartial);
completeNameFilter.Filters.Add(nameFilterLast);

queryExpression.Criteria = new FilterExpression(LogicalOperator.And);
queryExpression.Criteria.Filters.Add(emailFilter);
queryExpression.Criteria.Filters.Add(completeNameFilter);

queryExpression.AddOrder(Contact.Fields.LastName, OrderType.Descending);

//this is the problem part - it doesn't seem to do anything.
LinkEntity linkedFunctions = new LinkEntity(Contact.EntityLogicalName, pix_functie.EntityLogicalName, 
    Contact.Fields.Id, pix_functie.Fields.pix_Persoon, JoinOperator.LeftOuter);
linkedFunctions.Columns = new ColumnSet(pix_functie.Fields.Id, pix_functie.Fields.pix_Organisatie, 
    pix_functie.Fields.pix_isgzgfunction, pix_functie.Fields.pix_omschrijving, pix_functie.Fields.CreatedOn);
linkedFunctions.EntityAlias = ConfigKeys.PixFunctieAlias;

FilterExpression accountFilterExpression = new FilterExpression();
//accountFilterExpression.Conditions.Add(new ConditionExpression(pix_functie.Fields.pix_isgzgfunction, ConditionOperator.Equal, true));

linkedFunctions.AddLink(Account.EntityLogicalName, pix_functie.Fields.pix_Organisatie, Account.Fields.Id, JoinOperator.LeftOuter);
linkedFunctions.LinkEntities[0].LinkCriteria = accountFilterExpression;
linkedFunctions.LinkEntities[0].EntityAlias = "linkedAccountAlias";

queryExpression.LinkEntities.Add(linkedFunctions);

request.Query = queryExpression;

RetrieveMultipleResponse response = (RetrieveMultipleResponse)_context.Execute(request);

这让我从Function链接实体获取数据没问题，然后我对其进行分组、排序和处理：

    IEnumerable<Microsoft.Xrm.Sdk.Entity> entities = response.EntityCollection.Entities   
            .OrderByDescending(x => (x.GetAttributeValue<AliasedValue>(ConfigKeys.PixFunctieAlias + "." + pix_functie.Fields.pix_isgzgfunction) != null ? (bool?)
                x.GetAttributeValue<AliasedValue>(ConfigKeys.PixFunctieAlias + "." + pix_functie.Fields.pix_isgzgfunction).Value : new Nullable<bool>()).HasValue)
            .ThenByDescending(x => (x.GetAttributeValue<AliasedValue>(ConfigKeys.PixFunctieAlias + "." + pix_functie.Fields.pix_isgzgfunction) != null ? (bool?)
                x.GetAttributeValue<AliasedValue>(ConfigKeys.PixFunctieAlias + "." + pix_functie.Fields.pix_isgzgfunction).Value : null))
            .ThenByDescending(x => (x.GetAttributeValue<AliasedValue>(ConfigKeys.PixFunctieAlias + "." + pix_functie.Fields.CreatedOn) != null ? (DateTime?)
                x.GetAttributeValue<AliasedValue>(ConfigKeys.PixFunctieAlias + "." + pix_functie.Fields.CreatedOn).Value : new Nullable<DateTime>()).HasValue)
            .ThenByDescending(x => (x.GetAttributeValue<AliasedValue>(ConfigKeys.PixFunctieAlias + "." + pix_functie.Fields.CreatedOn) != null ? (DateTime?)
                x.GetAttributeValue<AliasedValue>(ConfigKeys.PixFunctieAlias + "." + pix_functie.Fields.CreatedOn).Value : null));


    List<TtNugGzgDataContract.Entities.Contact> lvl1Contacts = new List<TtNugGzgDataContract.Entities.Contact>();
    List<TtNugGzgDataContract.Entities.Contact> lvl2Contacts = new List<TtNugGzgDataContract.Entities.Contact>();

    foreach(var entity in entities)
    {
        Contact contact = entity.ToEntity<Contact>();
        TtNugGzgDataContract.Entities.Contact contactToAdd = new TtNugGzgDataContract.Entities.Contact()
        {
            externalID = contact.Id,
            firstname = contact.FirstName,
            lastname = contact.LastName,
            insertion = contact.MiddleName,
            gender = Converter.GetApiGender(contact.GenderCodeEnum),
            phone = !String.IsNullOrEmpty(contact.Telephone2) ? contact.Telephone2 : contact.MobilePhone,
            newsletter = contact.pix_GastlessenoptinEnum == pix_nieuwsbriefoptin.Toestaan
        };


        contactToAdd.entityID = entity.GetAttributeValue<AliasedValue>("linkedAccountAlias" + "." + Account.Fields.pix_GZGId) != null ?
            (string)entity.GetAttributeValue<AliasedValue>("linkedAccountAlias" + "." + Account.Fields.pix_GZGId).Value : null;

        contactToAdd.function = entity.GetAttributeValue<AliasedValue>(ConfigKeys.PixFunctieAlias + "." + pix_functie.Fields.pix_omschrijving) != null ?
            (string)entity.GetAttributeValue<AliasedValue>(ConfigKeys.PixFunctieAlias + "." + pix_functie.Fields.pix_omschrijving).Value : null;

        contactToAdd.isGzg = entity.GetAttributeValue<AliasedValue>(ConfigKeys.PixFunctieAlias + "." + pix_functie.Fields.pix_isgzgfunction) != null ?
            (bool?)entity.GetAttributeValue<AliasedValue>(ConfigKeys.PixFunctieAlias + "." + pix_functie.Fields.pix_isgzgfunction).Value : null;

        contactToAdd.createdOn = entity.GetAttributeValue<AliasedValue>(ConfigKeys.PixFunctieAlias + "." + pix_functie.Fields.CreatedOn) != null ?
            (DateTime?)entity.GetAttributeValue<AliasedValue>(ConfigKeys.PixFunctieAlias + "." + pix_functie.Fields.CreatedOn).Value : null;

        EntityReference reference = entity.GetAttributeValue<AliasedValue>(ConfigKeys.PixFunctieAlias + "." + pix_functie.Fields.pix_Organisatie) != null ?
            (EntityReference)entity.GetAttributeValue<AliasedValue>(ConfigKeys.PixFunctieAlias + "." + pix_functie.Fields.pix_Organisatie).Value : null;



        contactToAdd.accId = (entity.GetAttributeValue<AliasedValue>(ConfigKeys.PixFunctieAlias + "." + pix_functie.Fields.pix_Organisatie) != null ?
            (EntityReference)entity.GetAttributeValue<AliasedValue>(ConfigKeys.PixFunctieAlias + "." + pix_functie.Fields.pix_Organisatie).Value : new EntityReference()).Id;


        if (!String.IsNullOrEmpty(contact.EMailAddress1) && contact.EMailAddress1.Equals(email, StringComparison.InvariantCultureIgnoreCase))
        {
            contactToAdd.email = contact.EMailAddress1;
            contactToAdd.isSecondaryEmail = false;
            lvl1Contacts.Add(contactToAdd);
        } else
        {
            contactToAdd.email = contact.EMailAddress2;
            contactToAdd.isSecondaryEmail = true;
            lvl2Contacts.Add(contactToAdd);
        }
    }

但我无法从嵌套链接实体中获取entityID 。 AFAIK 别名是正确的，我什至尝试在它前面加上第一级链接实体的别名，但没有效果。

谁能指出我正确的方向？

Answer 1

我建议您不要使用手动滚动QueryExpression的方法来为您完成此任务。

1. 下载并安装XrmToolBox（ http://www.xrmtoolbox.com ）。
2. 从插件商店（在工具菜单上）下载FetchXml Builder。
3. 在图形界面中使用FetchXml构建查询。
4. 在视图菜单上，选择“ QueryExpression”。
5. 右侧将弹出一个窗口，向您显示为FetchXml查询生成的QueryExpression。

希望有帮助！

Answer 2

我一直在尝试不同的方法从“嵌套”层次结构中的多个层中获取属性。

也许我不明白 FetchXML 应该如何工作，当我在父表中指定属性时，子表属性不显示。