[英]How to Exclude Class in Parent Xpath Class? PHP
就是这样,把我推上墙
<div class="product-intro"><p class="product-desc"><span class="product-model">234</span>Product Description</p></div>
不是这样的...无效的参数,找不到节点:
$node3 = $xp->query("//p[@class='product-desc and not(@class='product-model']");
$node3 = $xp->query("//p[@class='product-desc'][not([@class='product-model'])]");
仅此一项:
$node3 = $xp->query("//p[@class='product-desc']");
只要获得结果,效果就很好,很好。 输出是
234产品描述
我知道我可以做一个字符串替换,但不是理想情况。.如何在查询中排除product-model
类?
整个脚本:
$x = '<div class="product-item productContainer" data-itemno="234">
<div class="product-and-intro">
<div class="product">
<a href="/en/234.html" title="Product Description">
<img src="/ProductImages/106/234.jpg" alt="Product Description" class="itemImage" />
<div class="product-intro">
<p class="product-desc"><span class="product-model">234</span>Product Description</p>
<p class="price"><span class="us">US$</span>6.50 <span class="oldprice"><s>$ 13.00</s></span></p>
</div>
</a>
</div>
</div>
</div>';
$dom = new DOMDocument();
libxml_use_internal_errors(true);
$dom->loadHTML($x);
$xp = new DOMXPath($dom);
$node1 = $xp->query("//div[@class='product']//img");
$node2 = $xp->query("//span[@class='product-model']");
$node3 = $xp->query("//p[@class='product-desc']");
// $node3 = $xp->query("//p[@class='product-desc']/text()[2]");
// $node3 = $xp->query("//p[@class='product-desc' and not(span/@class='product-model')]");
$node4 = $xp->query("//p[@class='price']");
foreach ($node1 as $n) {
echo $n->getAttribute('src');
echo '<br>';
}
foreach ($node2 as $n2) {
echo $n2->nodeValue;
echo '<br>';
}
foreach ($node3 as $n3) {
echo $n3->nodeValue;
echo '<br>';
}
foreach ($node4 as $n4) {
echo $n4->nodeValue;
echo '<br>';
}
如果要选择具有@class
属性值product-desc
所有p
元素,然后过滤掉具有@class
属性值product-model
的span
子元素的元素,则可以使用以下XPath表达式:
//p[@class='product-desc' and not(span/@class='product-model')]
或整体而言
$node3 = $xp->query("//p[@class='product-desc' and not(span/@class='product-model')]");
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