[英]ms-access-2010 returns #func[exclamation mark]
我有一个包含一个开关的sql语句,我想在ms-access-2010上执行。
SQL:
SELECT
TABLE_1.ID,
SWITCH
(
(TABLE_3.ID IN (7,8) AND TABLE_1.SOME_COLUMN = 2), (SELECT MAX(TABLE_4.ID) FROM TABLE_4 WHERE TABLE_4.TABLE_2_ID = TABLE_2.ID),
(SELECT MIN(TABLE_4.SOME_COLUMN) FROM TABLE_4 WHERE TABLE_4.TBL_2_ID = TABLE_1.TBL_2_ID)
)AS SOME_ALIAS
FROM
((TABLE_1
LEFT JOIN TABLE_2 ON TABLE_1.TABLE_2_ID = TABLE_2.ID)
LEFT JOIN TABLE_3 ON TABLE_2.TABLE_3_ID = TABLE_3.ID)
在我的结果中,“ some_column”列始终为#Function!
如果我不使用切换语句,而是将两种情况下的子选择添加为普通选择字段,如下所示:
SELECT
TABLE_1.ID,
(SELECT MAX(TABLE_4.ID) FROM TABLE_4 WHERE TABLE_4.TABLE_2_ID = TABLE_2.ID) AS SOME_COLUMN_1,
(SELECT MIN(TABLE_4.SOME_COLUMN) FROM TABLE_4 WHERE TABLE_4.TBL_2_ID = TABLE_1.TBL_2_ID) AS SOME_COLUMN_2
FROM
((TABLE_1
LEFT JOIN TABLE_2 ON TABLE_1.TABLE_2_ID = TABLE_2.ID)
LEFT JOIN TABLE_3 ON TABLE_2.TABLE_3_ID = TABLE_3.ID)
我没有任何问题(在SOME_COLUMN_1和SOME_COLUMN_2内只有几行没有值)。
是什么导致#FUNCTION!
的结果#FUNCTION!
这里?
Switch
语句需要偶数个参数。 您仅传递了3个参数,从而导致错误。
您可以使用IIF
,也可以添加其他比较参数(如果第一个参数不是true,则如果要返回最后一个参数,则可能只是True
作为第三个参数)。
SELECT
TABLE_1.ID,
IIF
(
(TABLE_3.ID IN (7,8) AND TABLE_1.SOME_COLUMN = 2), (SELECT MAX(TABLE_4.ID) FROM TABLE_4 WHERE TABLE_4.TABLE_2_ID = TABLE_2.ID),
(SELECT MIN(TABLE_4.SOME_COLUMN) FROM TABLE_4 WHERE TABLE_4.TBL_2_ID = TABLE_1.TBL_2_ID)
)AS SOME_ALIAS
FROM
((TABLE_1
LEFT JOIN TABLE_2 ON TABLE_1.TABLE_2_ID = TABLE_2.ID)
LEFT JOIN TABLE_3 ON TABLE_2.TABLE_3_ID = TABLE_3.ID)
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