PHP - 在邮件发送器中的变量 $message 中回显

Question

你好，我在邮件发送者的 PHP 回显代码中遇到了一个变量$folder的问题。 一切正常，但代码没有显示图像，可能是我在这里犯了错误。

<?php 
if(isset($_POST['submit'])){
    $to = "mail@my.mail.com"; // this is your Email address
    $from = "MYSELF"; // this is the sender's Email address
    $first_name = "A";
    $last_name = "B";
    $subject = "Hello!";
    $subject2 = "X";
    $headers = "From:" . $from;
    $headers = "MIME-Version: 1.0\r\n";
    $headers = "Content-Type: text/html; charset=UTF-8\r\n";
    $message= "
    <tr>
        <td><b>Subname</b></br>".$_POST["Subname"]."</td>
        <td rowspan='10'></br><img src='".$folder."'width='200' height='200'></td>
    </tr>";
    mail($to,$subject,$message,$headers);
    }
?>

在普通的 PHP 代码中，我有这个并且图像显示正确，但是我将“echo”移动到 mailsender 中的$message它不起作用。

<?php

    if(isset($_POST['submit'])){

        $file_name = $_FILES['file']['name'];
        $temp_name = $_FILES['file']['tmp_name'];
        $folder = "upload/".$file_name;

        move_uploaded_file($temp_name, $folder);
        echo "<img src='$folder' width='200' height='200'>";
    }
?>

Answer 1

您的第二个 PHP 代码$folder指向一个目录并且它可以正常工作。

但是要让它在您的$message ， $folder 需要是图像的链接。 类似于http://example.com/image.png

<?php 
if(isset($_POST['submit'])){ 
    $folder = "http://example.com/image.png";

    $to = "mail@my.mail.com"; // this is your Email address
    $from = "MYSELF"; // this is the sender's Email address
    $first_name = "A";
    $last_name = "B";
    $subject = "Hello!";
    $subject2 = "X";
    $headers = "From:" . $from;
    $headers = "MIME-Version: 1.0\r\n";
    $headers = "Content-Type: text/html; charset=UTF-8\r\n";
    $message= "
    <tr>
        <td><b>Subname</b></br>".$_POST["Subname"]."</td>
        <td rowspan='10'></br><img src='".$folder."'width='200' height='200'></td>
    </tr>";
    mail($to,$subject,$message,$headers);
    }
?>