[英]SQL Server cumulative SUM of a DATEDIFF into a percentage
我正在尝试从一些基本数据中将DATEDIFF的累积总和转换为一定百分比,这是一个小快照:
ID IIn IOut
AB123 2015-11-06 15:24:44.057 2015-11-14 01:00:00.000
QA565 2015-10-27 20:12:19.753 2015-11-06 03:00:00.000
UN555 2015-12-29 06:29:23.417 2016-01-03 08:00:00.000
LG602 2015-08-07 16:52:13.573 2015-08-11 03:00:00.000
ETC ETC
然后,我使用DATEDIFF获得几天的时间:
SELECT ID, DATEDIFF(hour, IIn, IOut)/24.0 IDays
FROM TimeTable
这给了我:
ID IDays
AB123 7.416666
QA565 9.291666
UN555 5.083333
LG602 3.458333
我想要的是ID
的计数IDay
(向下舍入),从最低IDay
到最高IDay
%的累积百分比,如下所示:
ID IDays IDaysPer
LG602 3 12.5
UN555 5 33.33
AB123 7 62.49
QA565 9 100
您可以使用几个窗口聚合来完成此操作,为方便起见将原始查询放在CTE中(子查询也可以):
declare @timeTable table (ID char(5) not null, IIn datetime not null,
IOut datetime not null)
insert into @timeTable(ID,IIn,IOut) values
('AB123','2015-11-06T15:24:44.057','2015-11-14T01:00:00.000'),
('QA565','2015-10-27T20:12:19.753','2015-11-06T03:00:00.000'),
('UN555','2015-12-29T06:29:23.417','2016-01-03T08:00:00.000'),
('LG602','2015-08-07T16:52:13.573','2015-08-11T03:00:00.000')
;With Diffs as (
SELECT ID, DATEDIFF(hour, IIn, IOut)/24.0 IDays
FROM @timeTable
)
select
*,
(
SUM(IDays) OVER (ORDER BY IDays, ID)
/
SUM(IDays) OVER ()
) * 100 as IDaysPer
from
Diffs
order by IDays
请注意,我不太了解您的“四舍五入”要求,但您应该能够使用围绕适当的计算方法包装的任何通用四舍五入技术。 所以我的输出与您的输出不太匹配:
ID IDays IDaysPer
----- --------------------------------------- ---------------------------------------
LG602 3.458333 13.696300
UN555 5.083333 33.828300
AB123 7.416666 63.201300
QA565 9.291666 100.000000
在这里,您可以:输出与您的匹配...
create table #TEMp
(ID VARCHAR(100)
,IIn datetime
,IOut datetime
)
insert into #temp(ID,IIn,IOut) values
('AB123','2015-11-06T15:24:44.057','2015-11-14T01:00:00.000'),
('QA565','2015-10-27T20:12:19.753','2015-11-06T03:00:00.000'),
('UN555','2015-12-29T06:29:23.417','2016-01-03T08:00:00.000'),
('LG602','2015-08-07T16:52:13.573','2015-08-11T03:00:00.000')
select ID,IDays AS Idays,ROUND(CAST(SUM(IDays) OVER(ORDER BY IDays) AS FLOAT)/CAST(SUM(IDays)OVER() AS FLOAT) * 100,2) AS IdaysPer
from
(
select *,ROUND(DATEDIFF(hour, IIn, IOut)/24,0) IDays
from #TEMP
)T
考虑时间表已经有数据
WITH t1 (ID, IDays)
AS (
SELECT ID, DATEDIFF(hour, IIn, IOut) / 24.0 AS IDays
FROM TimeTable
)
SELECT
ID, FLOOR(IDays),
(FLOOR(IDays) / (SELECT SUM(FLOOR(IDays)) FROM t1 t2 WHERE t1.IDays <= t2.IDays)) * 100.0 AS IDaysPer
FROM t1
ORDER BY 2 ASC
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