[英]Trying to Input to a member of a struct inside a vector of structs causes segmentation fault
我正在做一个项目,正在为一家假餐厅编写自动计费系统。 该程序应该获取包含菜单的文本文件,将其放入结构的数组或向量中,显示菜单,让客户订购并打印收据。 我在菜单中使用结构的全局向量。
此代码块是与问题相关的所有内容。
`
#include <iostream>
#include <fstream>
#include <vector>
//there is more code to this program, but the fault occurs very soon in the program
//and none of the rest of the code has any relevance.
//also, I don't really think that the problem is with trying to input, but I don't have enough experience to rule it out.
using namespace std;
struct menuItemType
{
string menuItem; //this is the name of the item
double menuPrice; // this is the price of the item
int menuCount;
};
vector<menuItemType> menuList; //the menu can be any size so I don't know how big it will be at this point. I'm using a vector to avoid having to declare a size
// I also have 2 other functions and some extra code in main that all need to access this vector. That is why I made it global
void getData() //this function opens the text file containing the menu and tries to read in each line.
{
ifstream input;
input.open("inData.txt");
input.peek();
int i = 0;
string item;
double price;
while(!input.eof())
{
getline(input,menuList[i].menuItem); //This is the line creating the fault.
input >> menuList[i].menuPrice;
i++;
input.peek();
}
}
int main()
{
getData();
return 0;
}
`
我尝试调试,并确定分段错误不是特定于代码片段中注释的行。 每当我尝试输入向量内部结构的成员时,似乎都会发生错误。 我也尝试过使用cin
,所以我不认为文本文件流是问题。 文本文件如下所示:
Bacon and eggs 1.00 Muffin 0.50 Coffee 0.90
具体来说,我的问题是:为什么尝试在向量内部输入结构的成员会导致分割错误,以及如何解决该错误。
抱歉,冗长的解释和笨拙的格式。 我对堆栈溢出和c ++还是相当陌生。
从文件中检索数据时; 我倾向于检索单行的内容并将其存储到某个字符串,流或缓冲区中,然后在以后进行解析,或者我将检索文件的全部内容并执行相同的操作。 从文件中提取数据并关闭其句柄之后,我发现解析字符串更容易。 我不喜欢使用不是CONST的全局变量。 同样,当从文件while( file.eof() )
或while ( !file.eof() )
读取文件时,使用for循环的方式也是不好的做法,以后可能会导致许多错误,崩溃和头痛。 如果您从下面查看我的函数,它会使用一个文件名并尝试打开它(如果存在)。 一旦打开,它将得到一条线,将其保存到字符串中并将该字符串推入向量中,直到没有其他要读取的内容为止。 然后,它关闭文件句柄并返回。 这符合具有单一职责的功能的概念。
如果您具有打开文件,读一行,解析数据,读一行,解析数据等功能,然后关闭它; 这种功能被认为可以承担多项任务,这可能是一件坏事。 首先是性能原因。 可以这么说,打开和读取文件本身是一项计算量很大的任务。 您还尝试动态创建对象,如果您从未检查过从文件中接收到的值,这可能会很糟糕。 在下面查看我的代码,您将看到我所指的设计模式,其中每个功能都有自己的职责。 这也有助于防止file corruption
。
#include <vector>
#include <string>
#include <sstream>
#include <iostream>
#include <fstream>
#include <exception>
struct MenuItem {
string menuItem;
double menuPrice;
int menuCount;
};
// This function is not used in this case but is a very helpful function
// for splitting a string into a vector of strings based on a common delimiter
// This is handy when parsing CSV files {Comma Separated Values}.
std::vector<std::string> splitString( const std::string& s, char delimiter ) {
std::vector<std::string> tokens;
std::string token;
std::istringstream tokenStream( s );
while( std::getline( tokenStream, token, delimiter ) ) {
tokens.push_back( token );
}
return tokens;
}
void getDataFromFile( const char* filename, std::vector<std::string>& output ) {
std::ifstream file( filename );
if( !file ) {
std::stringstream stream;
stream << "failed to open file " << filename << '\n';
throw std::runtime_error( stream.str() );
}
std::string line;
while( std::getline( file, line ) ) {
if ( line.size() > 0 )
output.push_back( line );
}
file.close();
}
void parseFileData( const std::vector<std::string>& fileContents, std::vector<MenuItem> menuItems ) {
// The first param is the contents of the file where each line
// from the file is stored as a string and pushed into a vector.
// Here you need to parse this data. The second parameter is the
// vector of menu items that is being passed by reference.
// You can not modify the fileContents directly as it is const and read only
// however the menuItems is passed by reference only so you can update that
// This is where you will need to go through some kind of loop and get string
// of text that will stored in your MenuItem::menuItem variable.
// then the next string will have your price. Here you showed that your
// text file has `$` in front of the value. You will then have to strip this out
// leaving you with just the value itself.
// Then you can use `std::stod( stringValue ) to convert to value,
// then you can save that to MenuTiem::menuPrice variable.
// After you have the values you need then you can push back this temp MenuItem
// Into the vector of MenuItems that was passed in. This is one iteration of
// your loop. You continue this until you are done traversing through the fileContents vector.
// This function I'll leave for you to try and write.
}
int main() {
try {
std::vector<std::string> fileConents;
getDataFromFile( "test.txt", fileConents );
std::vector<MenuItem> data; // here is the menu list from your example
generateVectors( fileConents, data );
// test to see if info is correct
for( auto& d : data ) {
std::cout << data.menuItem << " " << data.menuPrice << '\n';
}
} catch( const std::runtime_error& e ) {
std::cerr << e.what() << '\n';
return EXIT_FAILURE;
}
return EXIT_SUCCESS;
}
至于您的错误或崩溃,您可能是访问了超出向量结尾的索引,或者您尝试使用向量中包含无效数据的内容。
如果查看向量的operator [],然后检查异常部分,它将告诉您,如果n大于向量的大小,则实际上是未定义的行为。 您可能想要回退事先创建的项目。
我通常更喜欢vector :: at,因为它经过边界检查,并通过引发out_of_range异常来发出信号,指示所请求的位置是否超出范围。
首先从inData.txt中删除“ $”,然后建议像这样使用while(getline(input,item)):
#include <iostream>
#include <fstream>
#include <vector>
#include <math.h>
//there is more code to this program, but the fault occurs very soon in the program
//and none of the rest of the code has any relevance.
//also, I don't really think that the problem is with trying to input, but I don't have enough experience to rule it out.
using namespace std;
struct menuItemType
{
string menuItem; //this is the name of the item
double menuPrice; // this is the price of the item
int menuCount;
};
vector<menuItemType*> menuList; //the menu can be any size so I don't know how big it will be at this point. I'm using a vector to avoid having to declare a size
// I also have 2 other functions and some extra code in main that all need to access this vector. That is why I made it global
void getData() //this function opens the text file containing the menu and tries to read in each line.
{
ifstream input;
input.open("inData.txt");
int i = 0;
string item;
double price;
while(getline(input, item))
{
menuList.push_back(new menuItemType);
menuList[i]->menuItem = item;
getline(input,item);
menuList[i]->menuPrice = atof((char*)item.c_str()); //math.h
i++;
}
}
int main()
{
getData();
for(menu : menuList)
{
cout << menu->menuItem << ": " << menu->menuPrice << endl;
delete menu; //cleaning memory
}
return 0;
}
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