如何创建swagger数组

Question

我正在尝试创建一个低于JSON的swagger文档，但我得到以下错误： 带有'type：array'的模式，需要兄弟'items：'字段

JSON：

{
    "_id": "string",
    "name": "string",
    "descriptions": {},
    "date": "string",
    "customer": {
        "id": "string",
        "name": {
            "firstName": "string",
            "lastName": "string",
            "middleName": "string"
        }
    },
    "productDetials": {
        "id": "string",
        "name": {
            "name": "string",
            "model": "string",
            "price": "string",
            "comments": "string"
        }
    },
    "Phone": [{
            "id": "string",
            "category": "string",
            "version": "string",
            "condition": "string",
            "availability": "string"

        }
    ]   
}

有人可以帮助我获得这个JSON的swagger文档。

任何帮助将非常感激。

Answer 1

首先，您必须定义依赖于JSON（对象）的模型。

在你的情况下：

• Order （我猜）
• Customer
• CustomerName
• ProductDetails
• ProductName
• Phone

然后在YAML（Swagger模式文档）的definitions部分中定义模型：

Order:
  type: "object"
  properties:
    _id:
      type: "string"
    name:
      type: "string"
    descriptions:
      type: "object"
    date:
      type: "string"
    customer:
      $ref: "#/definitions/Customer"
    productDetails:
      $ref: "#/definitions/ProductDetails"
    phoneNumbers:
      type: "array"
      items:
        $ref: "#/definitions/Phone"
Customer:
  type: "object"
  properties:
    id:
      type: "string"
    name:
      $ref: "#/definitions/CustomerName"
CustomerName:       
  type: "object"
  properties:
    firstName:
      type: "string"
    lastName:
      type: "string"
    middleName:
      type: "string"
ProductDetails:
  type: "object"
  properties:
    id:
      type: "string"
    name:
      $ref: "#/definitions/ProductName"
ProductName:       
  type: "object"
  properties:
    name:
      type: "string"
    model:
      type: "string"
    price:
      type: "string"
    comments:
      type: "string"
Phone:
  type: "object"
  properties:
    id: 
      type: "string"
    category:
      type: "string"
    version:
      type: "string"
    condition:
      type: "string"
    availability:
      type: "string"

如果要将具有特定模型的数组定义为项目 - 将array作为type并定义items （根据提供的错误代码，您忘记了它）。 items是数组的内容 - 所以在你的情况下的Phone模型：

...
phoneNumbers:
  type: "array"
  items:
    $ref: "#/definitions/Phone"