完成Xquery的多个for循环

Question

我有如下的输入请求

<Input>
<BusinessObjects>
      <BusinessObject>
        <BusinessIdentifiers>
          <BusinessIdentifier>
            <BKey>BuCode</BKey>
            <BValue>CDC</BValue>
          </BusinessIdentifier>
          <BusinessIdentifier>
            <BKey>BuType</BKey>
            <BValue>123</BValue>
          </BusinessIdentifier>
          <BusinessIdentifier>
            <BKey>CsmNo</BKey>
            <BValue>857895</BValue>
          </BusinessIdentifier>
        </BusinessIdentifiers>
       </BusinessObject>
      <BusinessObject>
        <BusinessIdentifiers>
          <BusinessIdentifier>
            <BKey>BuCode</BKey>
            <BValue>CDC</BValue>
          </BusinessIdentifier>
          <BusinessIdentifier>
            <BKey>BuType</BKey>
            <BValue>123</BValue>
          </BusinessIdentifier>
          <BusinessIdentifier>
            <BKey>CsmNo</BKey>
            <BValue>34567</BValue>
          </BusinessIdentifier>
        </BusinessIdentifiers>
        </BusinessObject>      
    </BusinessObjects>
    </Input>

我需要形成如下架构的输出

<Output>
<BusinessObject>
<BIKey></BIKey>
<BKey></BIKey>
<Bvalue></Bvalue>
<BOID></BOID>
</BusinessObject>
</Output>

对于上述有效负载，输出应为

<Output>
<BusinessObjects>
<BusinessObject>
<BIKey>CDC:123:857895|CDC:123:34567</BIKey>
<BKey>BUCode</BKey>
<Bvalue>CDC</Bvalue>
<BOID>CDC:123:857895</BOID>
</BusinessObject>
<BusinessObject>
<BIKey>CDC:123:857895|CDC:123:34567</BIKey>
<BKey>BUtype</BKey>
<Bvalue>123</Bvalue>
<BOID>CDC:123:857895</BOID>
</BusinessObject>
<BusinessObject>
<BIKey>CDC:123:857895|CDC:123:34567</BIKey>
<BKey>CSMNo</BKey>
<Bvalue>857895</Bvalue>
<BOID>CDC:123:857895</BOID>
</BusinessObject>
<BusinessObject>
<BIKey>CDC:123:857895|CDC:123:34567</BIKey>
<BKey>BUCode</BKey>
<Bvalue>CDC</Bvalue>
<BOID>CDC:123:34567</BOID>
</BusinessObject>
<BusinessObject>
<BIKey>CDC:123:857895|CDC:123:34567</BIKey>
<BKey>BUtype</BKey>
<Bvalue>123</Bvalue>
<BOID>CDC:123:34567</BOID>
</BusinessObject>
<BusinessObject>
<BIKey>CDC:123:857895|CDC:123:34567</BIKey>
<BKey>CSMNo</BKey>
<Bvalue>857895</Bvalue>
<BOID>CDC:123:34567</BOID>
</BusinessObject>
</BusinessObjects>
</Output>

我曾尝试在Xquery下面获得相同的结果，但最终出现错误或不符合要求

<Ouput>
<BusinessObjects>
{
for $bi in Input/BusinessObjects/BusinessObject/BusinessIdentifiers/BusinessIdentifier
return
<BIKey>
    {
        string-join(
            for $bo in Input/BusinessObjects/BusinessObject return string-join($bo/BusinessIdentifiers/BusinessIdentifier/BValue, '|'),
            ':'
        )
    }
    </BIKey>
    <BKey>data {$bi/Bkey}</BKey>
    <Bvalue>data {$bi/Bvalue}</Bvalue>
    for $bo in Input/BusinessObjects/BusinessObject return <BOID>{string-join($bo//BValue, ':')}<BOID>

}
</BusinessObjects>
</Ouput>

输出字段的描述如下所示：BIKey->它由“ Business Identifier”的所有Bvalue组成，并以“：”连接，然后对于每个业务对象，将其以“ |”分隔。 Bkey->使用bkey的直接映射Bvalue->使用Bvalue的直接映射BOID->必须为每个业务对象形成，需要将值的业务标识符的Bvalues连接为'：'任何建议，我认为我都必须这里有两个复杂的循环，但无法破解。

谢谢

Answer 1

与查询

<Output>
    <BusinessObjects>
        {
            //BusinessIdentifier 
            ! 
            <BusinessObject>
                <BIKey>{string-join(ancestor::BusinessObjects/BusinessObject!string-join(.//BValue, ':'), '|')}</BIKey>
                {
                    BKey, 
                    BValue
                }
                <BOID>{ancestor::BusinessObject!string-join(.//BValue, ':')}</BOID>
            </BusinessObject>
        }
    </BusinessObjects>
</Output>

在https://xqueryfiddle.liberty-development.net/948Fn5g我得到了结果

<Output>
   <BusinessObjects>
      <BusinessObject>
         <BIKey>CDC:123:857895|CDC:123:34567</BIKey>
         <BKey>BuCode</BKey>
         <BValue>CDC</BValue>
         <BOID>CDC:123:857895</BOID>
      </BusinessObject>
      <BusinessObject>
         <BIKey>CDC:123:857895|CDC:123:34567</BIKey>
         <BKey>BuType</BKey>
         <BValue>123</BValue>
         <BOID>CDC:123:857895</BOID>
      </BusinessObject>
      <BusinessObject>
         <BIKey>CDC:123:857895|CDC:123:34567</BIKey>
         <BKey>CsmNo</BKey>
         <BValue>857895</BValue>
         <BOID>CDC:123:857895</BOID>
      </BusinessObject>
      <BusinessObject>
         <BIKey>CDC:123:857895|CDC:123:34567</BIKey>
         <BKey>BuCode</BKey>
         <BValue>CDC</BValue>
         <BOID>CDC:123:34567</BOID>
      </BusinessObject>
      <BusinessObject>
         <BIKey>CDC:123:857895|CDC:123:34567</BIKey>
         <BKey>BuType</BKey>
         <BValue>123</BValue>
         <BOID>CDC:123:34567</BOID>
      </BusinessObject>
      <BusinessObject>
         <BIKey>CDC:123:857895|CDC:123:34567</BIKey>
         <BKey>CsmNo</BKey>
         <BValue>34567</BValue>
         <BOID>CDC:123:34567</BOID>
      </BusinessObject>
   </BusinessObjects>
</Output>

在XQuery 1中，您没有! 简单的地图运算符，但您应该可以使用for .. return ，请参阅https://xqueryfiddle.liberty-development.net/948Fn5g/1

<Output>
    <BusinessObjects>
        {
            for $bi in //BusinessIdentifier 
            return  
            <BusinessObject>
                <BIKey>{string-join($bi/ancestor::BusinessObjects/BusinessObject/string-join(.//BValue, ':'), '|')}</BIKey>
                {
                    $bi/BKey, 
                    $bi/BValue
                }
                <BOID>{$bi/ancestor::BusinessObject/string-join(.//BValue, ':')}</BOID>
            </BusinessObject>
        }
    </BusinessObjects>
</Output>

或构造新元素的简单步骤，请参见https://xqueryfiddle.liberty-development.net/948Fn5g/2

<Output>
    <BusinessObjects>
        {
            //BusinessIdentifier/
            <BusinessObject>
                <BIKey>{string-join(ancestor::BusinessObjects/BusinessObject/string-join(.//BValue, ':'), '|')}</BIKey>
                {
                    BKey, 
                    BValue
                }
                <BOID>{ancestor::BusinessObject/string-join(.//BValue, ':')}</BOID>
            </BusinessObject>
        }
    </BusinessObjects>
</Output>