[英]Group by several columns with count on another column SQL Server
您可以将联合查询与一些条件SUM
一起使用。
SELECT
LastUpdate,
UpdatedBy as User,
SUM(CASE WHEN Status = 'A' THEN 1 ELSE 0 END) as A
SUM(CASE WHEN Status = 'C' THEN 1 ELSE 0 END) as C
SUM(CASE WHEN Status = 'D' THEN 1 ELSE 0 END) as D
SUM(CASE WHEN Status = 'Z' THEN 1 ELSE 0 END) as Z
SUM(CASE WHEN Status = 'X' THEN 1 ELSE 0 END) as X
FROM table
GROUP BY LastUpdate, UpdatedBy
ORDER BY LastUpdate, UpdatedBy
您可以尝试使用条件聚合
select LastUpdate,UpdatedBy,
count(case when Status='A' then UpdatedBy end) as 'A',
count(case when Status='C' then UpdatedBy end) as 'C',
count(case when Status='D' then UpdatedBy end) as 'D',
count(case when Status='Z' then UpdatedBy end) as 'Z',
count(case when Status='X' then UpdatedBy end) as 'X'
from tablename
group by LastUpdate,UpdatedBy
好吧,我在伙计们的帮助下弄清楚了
SELECT
CAST(LastUpdate as DATE),
UserName,
SUM(CASE WHEN Status = 1 THEN 1 ELSE 0 END) as [Status_1],
SUM(CASE WHEN Status = 2 THEN 1 ELSE 0 END) as [Status_2],
SUM(CASE WHEN Status = 3 THEN 1 ELSE 0 END) as [Status_3]
FROM Table
WHERE LastUpdate BETWEEN '2018-11-30 10:013:44.080' AND '2018-12-30 10:013:44.080'
GROUP BY CAST(LastUpdate as DATE), UserName
ORDER BY CAST(LastUpdate as DATE)
这是一个示例查询,我在其中查找两个日期之间的记录。 我遇到的问题部分是由于过滤了datetime而不是date。 lastupdate列是日期时间,因此通过强制转换为最新日期可以解决该问题
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