Swift Firebase动态链接：shorteningURL不起作用

Question

面对一些从firebase动态链接生成shortURL的问题，我能够获取longDynamicLink url。 但

这是我的代码，我正在使用https://firebase.google.com/docs/dynamic-links/ios/create以下步骤DynamicLinkComponents.shortenURL完成未得到调用，并且也没有错误

guard let longDynamicLink = linkBuilder.url else { return "test" }
print("The long URL is: \(longDynamicLink)")

DynamicLinkComponents.shortenURL(longDynamicLink, options: nil) { url, warnings, error in
    guard let url = url, error != nil else { return }
    print("The short URL is: \(url)")
}

DynamicLinkComponents.shortenURL此部分未执行

Answer 1

尝试此代码。 此代码对我来说很好。

    let shareLink:String = "http://YourURL"

    guard let newSharelink = URL(string: shareLink) else { return }
    let components = DynamicLinkComponents.init(link: newSharelink, domain: "Your Domin From Genrated By Google Account(EX. = napu4u.app.goo.gl)")
    let iOSParams = DynamicLinkIOSParameters(bundleID: "YourBundle ID")
    iOSParams.appStoreID = "Your AppStore ID (Optional)"

    components.iOSParameters = iOSParams
    let options = DynamicLinkComponentsOptions()
    options.pathLength = .short
    components.options = options

    components.shorten { (shortURL, warnings, error) in

        if let error = error {
            print(error.localizedDescription)
            return
        }

        let shortLink = shortURL
        print(shortLink)
    }

Answer 2

1. 将此添加到“应用功能-关联的域”，然后输入-applinks：yourdomain.com

2. 在您的ViewController中添加

    guard let link = URL(string: "https://www.yourdomain.com/share_location.html?Id=\\(RandomID)&uid=\\(uid)") else { return } let dynamicLinksDomain = "yourdomain.page.link" let components = DynamicLinkComponents(link: link, domain: dynamicLinksDomain) // [START shortLinkOptions] let options = DynamicLinkComponentsOptions() options.pathLength = .unguessable components.options = options // [END shortLinkOptions] // [START shortenLink] components.shorten { (shortURL, warnings, error) in // Handle shortURL. if let error = error { print(error.localizedDescription) return } print(shortURL?.absoluteString ?? "") self.shortLink = shortURL }