将工作查询合并为一个查询，并在结果集中包含多列

Question

我有2个基本查询，都按预期工作并返回预期结果：

select
  empNumber,
  sum(salesPrice) as categorySales
from testSchema.sales 
where empNumber = 12345
and date between '2018-01-01' and '2018-04-31'
and g.category = 'NewCategory'
group by empNumber;

select
  empNumber,
  sum(salesPrice) as totalSales
from testSchema.sales 
where empNumber = 12345
and date between '2018-01-01' and '2018-04-31'
group by empNumber;

但是，我想将它们组合成一个查询，该查询将每个结果作为自己的列返回。 目前，这两个查询之间的主要区别是附加的AND子句创建了一个特定的值。 目前的结果是

第一个查询：

empNumber  |  categorySales
----------------------------
12345               15603.00

第二个查询：

empNumber  |  totalSales
----------------------------
12345           350253.00

但我想找到一种高性能且可扩展的方式来将它们结合起来

所需结果：

empNumber  |  categorySales  |  totalSales
-----------------------------------------------
12345           15603.00            350253.00

实现此目标的最有效方式是什么，以便将来我可以添加更多子句并返回一个结果集？

Answer 1

合并两者的最简单方法（如果您没有重复的值）是FULL JOIN

尝试这个

with c as(
select
  empNumber,
  sum(salesPrice) as categorySales
from testSchema.sales 
where empNumber = 12345
and date between '2018-01-01' and '2018-04-31'
and g.category = 'NewCategory'
group by empNumber
), d as(
select
  empNumber,
  sum(salesPrice) as totalSales
from testSchema.sales 
where empNumber = 12345
and date between '2018-01-01' and '2018-04-31'
group by empNumber
)
Select isnull(c.empNumber,d.empNumber) as empNumber
      ,c.categorySales
      ,d.totalSales
  from c full join d ON (c.empNumber = d.empNumber)

Answer 2

将通用条件包括在where中where并有条件地where汇总，即使用case表达式。

select
  empNumber,
  sum(case when category = 'NewCategory' then salesPrice else 0 end) as categorySales,
  sum(salesPrice) as totalSales
from testSchema.sales 
where empNumber = 12345
and date between '2018-01-01' and '2018-04-30'
group by empNumber;