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[英]How to convert a Json list to a list of java objects with javax.json?
[英]Render JSON with two objects in javax.json
给定这两个带注释的类:
public class Clazz1 {
@JsonbProperty("val11")
String value11;
@JsonbProperty("val12")
String value12;
.....
}
public class Clazz2 {
@JsonbProperty("val21")
String value21;
@JsonbProperty("val22")
String value22;
.....
}
我需要生成一个包含两个对象的JSON,例如:
Clazz1 c1 = new Clazz1();
Clazz1 c2 = new Clazz2();
c1.setValue1("ABC");
... other settings
JsonObject json = Json.createObjectBuilder()
.add("c1", c1)
.add("c2", c2)
.build();
上面的add
方法不接受对象,如何创建同时包含对象c1
和c2
的JSON?
一种方法是使用JsonObjectBuilder
API并手动构建对象:
JsonBuilderFactory factory = Json.createBuilderFactory();
JsonObject value = factory.createObjectBuilder()
.add("c1", factory.createObjectBuilder()
.add("value11", c1.getValue11()))
.add("c2", factory.createObjectBuilder()
.add("value21", c1.getValue21()))
参考: https : //docs.oracle.com/javaee/7/api/javax/json/JsonObjectBuilder.html
另一种是使用JsonbBuilder
API:
JsonbConfig jsonbConfig = new JsonbConfig()
.withPropertyNamingStrategy(
PropertyNamingStrategy.LOWER_CASE_WITH_DASHES);
Map<String, Object> objectMap = new HashMap<>();
objectMap.put("c1", c1);
objectMap.put("c2", c2);
String json = JsonbBuilder.create(jsonbConfig).toJson(objectMap);
引用: https ://www.ibm.com/developerworks/library/j-javaee8-json-binding-3/index.html
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