使用angular.js在每行中为数据表jquery添加一个复选框

Question

我想是的，我想显示在一些数据datatable通过使用角度JS格式。

所以我做了下面的事情。

角

 <script src="~/Scripts/jquery.js"></script> <script src="~/Scripts/jquery.dataTables.min.js"></script> <script src="~/Scripts/angular.js"></script> <script src="~/Scripts/angular-datatables.js"></script> var app = angular.module('myapp', ['datatables']); app.controller('homectrl', ['$scope', '$http', 'dtoptionsbuilder', 'dtcolumnbuilder', function ($scope, $http, dtoptionsbuilder, dtcolumnbuilder) { $scope.dtcolumns = [ //dtcolumnbuilder.newcolumn("action", "action"), dtcolumnbuilder.newcolumn("objectid", "id"), dtcolumnbuilder.newcolumn("service_code", "service code"), dtcolumnbuilder.newcolumn("cond1", "condition 1"), dtcolumnbuilder.newcolumn("cond2", "condition 2"), dtcolumnbuilder.newcolumn("cond3", "condition 3"), dtcolumnbuilder.newcolumn("service_type", "service type"), dtcolumnbuilder.newcolumn("remark", "remark"), dtcolumnbuilder.newcolumn("description", "description") ] $scope.dtoptions = dtoptionsbuilder.newoptions().withoption('ajax', { url: "/home/getdata", type: "post" }) .withpaginationtype('full_numbers') .withdisplaylength(10); }]) 

 <div ng-app="MyApp" class="container" ng-controller="homeCtrl"> <div ng-controller="homeCtrl"> <table id="entry-grid" datatable="" dt-options="dtOptions" dt-columns="dtColumns" class="table table-hover"> </table> <br /> </div> 

和控制器

public ActionResult getdata()
    {
        DataTable dt = new DataTable();
        using (OracleConnection conn = new OracleConnection(System.Configuration.ConfigurationManager.ConnectionStrings["ConnAPP_NEIQC"].ToString()))
        {   
            GetData objGetData = new GetData();
            dt =  objGetData.GetDataForGrid();

            var circleList = (from DataRow dr in dt.Rows
                           select new 
                           {         
                               //Action = "",
                               OBJECTID = Convert.ToString(dr["OBJECTID"]),
                               SERVICE_CODE = Convert.ToString(dr["SERVICE_CODE"]),
                               COND1 = Convert.ToString(dr["COND1"]),
                               COND2 = Convert.ToString(dr["COND2"]),
                               COND3 = Convert.ToString(dr["COND3"]),
                               SERVICE_TYPE = Convert.ToString(dr["SERVICE_TYPE"]),
                               REMARK = Convert.ToString(dr["REMARK"]),
                               DESCRIPTION = Convert.ToString(dr["DESCRIPTION"]),
                           }).ToList();

            return Json(circleList, JsonRequestBehavior.AllowGet);
        }
    }

现在我想要的是，我想在每行中添加一个CHECKBOX ，以便我可以编辑和更新其记录。 有谁可以帮助我做到这一点。

Answer 1

是这个吗？选择插件。 withSelect

Answer 2

如yujinpan所述，您可以使用select扩展名。 或者只是自己渲染一个复选框：

$scope.dtcolumns = [
  dtcolumnbuilder.newcolumn(null, '').renderWith(function(data, type, full)
     return '<input type="checkbox" class="check" data-object-id="'+full.objectid+'">'
  }),
  dtcolumnbuilder.newcolumn("objectid", "id"),
  ...
]

现在，您可以通过.check类将委派的事件处理程序与复选框相关联。

---

使用dtInstance作为解释这里或文档这里 （看页面的底部）。 现在你可以做类似的事情

$('#entry-grid').on('click', '.check', function() {
   var data = $scope.dtInstance.DataTable.row($(this).closest('tr')).data()
})