如何使用多个定界符将字符串简化为自定义对象，未捕获（承诺）：TypeError：无法读取未定义的属性

Question

我有一个以下格式的字符串...

“ 6:00 AM-起床，铺床，刷牙。6:45 AM-洗澡。7:15 AM-吃早餐，上学。”

我想根据句号，逗号和破折号来减少该字符串。 基本上得到一个具有时间和活动的对象。 对象应该看起来像这样...

{
  6:00AM: ['Get up', 'Make the bed', 'Brush my teeth'],
  6:45AM: ['Take a shower'],
  7:15AM: ['Have breakfast', 'Leave for school']
}

我该怎么做呢？ 我不太清楚。

以下是我添加的内容。

现在，我有一个来自数据库的对象，看起来像这样...

[
  {
    "id": 1,
    "day": "Monday",
    "activities": "6:00AM - Get up, Make the bed, Brush my teeth. 6:45AM - Take a shower. 7:15AM - Have breakfast, Leave for school."
  },
  {
    "id": 2,
    "day": "Tuesday",
    "activities": "6:00AM - Get up, Make the bed, Brush my teeth. 6:45AM - Take a shower. 7:15AM - Have breakfast, Leave for school."
  }
]

我想遍历该数组，并用转换后的字符串（即返回的对象）替换每个activities属性的值。 因此，我创建了一个单独的变量，称为activity，并将其实例化为一个数组，在该数组中我希望存储从转换activity property返回的对象。 所以..

let activities = [];

/* My function */ 
private splitter() {
  const activities = this.itinerary.map(item => {
    return item.activities;
  });

  const results = {};
  const res = activities.map(str => {
    for (const result of str.split('.').map(x => x.trim())) {
      if (result) {
        const [time, actions] = result.split(' - ');
        results[time] = actions.split(',').map(x => x.trim());
      }
    }
    return results;
  });
  return res;
}

我希望能达到这样的目标...

[
    {
      6:00AM: ['Get up', 'Make the bed', 'Brush my teeth'],
      6:45AM: ['Take a shower'],
      7:15AM: ['Have breakfast', 'Leave for school']
    },
    {
      6:00AM: ['Get up', 'Make the bed', 'Brush my teeth'],
      6:45AM: ['Take a shower'],
      7:15AM: ['Have breakfast', 'Leave for school']
    }
]

但是，我得到了错误...

Uncaught (in promise): TypeError: Cannot create property '6:00AM' on string '6:00AM - Get up, Make the bed, Brush my teeth.'

我该如何工作？

Answer 1

这将使用仅可在任何最新版本的Node.JS中运行的内置JavaScript来解决问题：

const str = "6:00AM - Get up, Make the bed, Brush my teeth. 6:45AM - Take a shower. 7:15AM - Have breakfast, Leave for school."

sentences = {};
// split the string on periods, and trim each sentence
for (sentence of str.split('.').map(x => x.trim())) {
    // you end up with a completely empty sentence when the last
    // sentence ends in a period, which is uninteresting
    if (sentence) {
        // split each sentence on a hyphen, and assume the first
        // element is time and the second is actions
        let [time, actions] = sentence.split(' - ');

        // split the actions string on commas and trim whitespace;
        // store that in our sentences object
        sentences[time] = actions.split(',').map(x => x.trim());
    }
}

然后最后的console.log(sentences)为您提供：

{ '6:00AM': [ 'Get up', 'Make the bed', 'Brush my teeth' ],
  '6:45AM': [ 'Take a shower' ],
  '7:15AM': [ 'Have breakfast', 'Leave for school' ] }

Answer 2

也许这是一个非常幼稚的解决方案，但是您可以结合使用split和map来解决类似的问题。

假设您有字符串。 您可以开始使用第一个最大的分隔符（在此示例中为句点）对其进行分割。

const string = "6:00AM - Get up, Make the bed, Brush my teeth. 6:45AM - Take a shower. 7:15AM - Have breakfast, Leave for school."
const firstSplit = string.split(".");

您现在在firstSplit所拥有的内容类似于["6:00AM - Get up, Make the bed, Brush my teeth", "6:45AM - Take a shower", "7:15AM - Have breakfast, Leave for school"] firstSplit ["6:00AM - Get up, Make the bed, Brush my teeth", "6:45AM - Take a shower", "7:15AM - Have breakfast, Leave for school"] 。 您现在可以做的是将该数组中的每个值进一步拆分为小时并激活。

由于我想拆分数组中的每个项目（使用结果获取一个新数组），因此我将使用一个map

const secondSplit = firstSplit.map(each => each.split(" - "))

现在， secondSplit看起来像[["6:00AM", "Get up, Make the bed, Brush my teeth"], ["6:45AM", "Take a shower"], ["7:15AM", "Have breakfast, Leave for school"]]

现在，将这个奇怪的数组数组转换为一个对象，其中每个小数组的第一个位置是键，第二个是值。 我将使用vainilla javascript，但是当然可以使用任何js库（例如lodash或ramda）来简化

const almostThere = secondSplit.reduce((object, subarray) => {
  object[subarray[0]] = subarray[1]
  return object
}, {})

这真是难以置信，接近您的实际需求。 该对象看起来像：

{
  6:00AM: "Get up, Make the bed, Brush my teeth",
  6:45AM: "Take a shower",
  7:15AM: "Have breakfast, Leave for school"
}

注意，我们在每个对象值上都缺少一个拆分。 我们可以通过修改以前完成的reduce来解决

const yeay = secondSplit.reduce((object, subarray) => {
  object[subarray[0]] = subarray[1].split(", ")
}, {})

然后你走了！

总共看起来可能像这样：

const firstSplit = string.split(".")
 .map(each => each.split(" - "))
 .reduce((object, subarray) => {
  object[subarray[0]] = subarray[1].split(", ")
  return object
}, {})

可以针对以下内容进行优化：

const yeay = string.split(".")
 .reduce((object, hourAndChores) => {
    const splittedHourAndChores = hourAndChores.split(" - ");
    object[splittedHourAndChores[0]] = splittedHourAndChores[1].split(", ")
    return object
}, {})