[英]How to create a new property in a array object based on a condition in TypeScript
[英]How to merge the array property of an object based on a condition?
如何将两个对象合并在一起。 并在每次数字匹配时将新对象添加到正文中? 我尝试了传播算子,但它覆盖了值而不是更改它。
之前:
let obj = {
number: "123",
body:[
{
id:'client',
text:'hi'
}
]
}
let obj2 = {
number: "123",
body:[
{
id:'client',
text:'Hello there'
}
]
}
我需要将它们合并为:
obj = {
number: "123",
body:[
{
id:'client',
text:'hi'
},
{
id:'client',
text:'Hello there'
}
]
}
只需检查number
键在两种情况下是否相等,然后迭代obj2.body
并将其推入obj.body
中obj.body
let obj = { number: "123", body: [{ id: 'client', text: 'hi' }] } let obj2 = { number: "123", body: [{ id: 'client', text: 'Hello there' }] } if (obj2.number === obj.number) { obj2.body.forEach(item => { obj.body.push(item) }) } console.log(obj)
如果只有两个对象,您可以这样做
if (obj.number == obj2.number) {
obj.body = obj.body.concat(obj2.body)
console.log("Here's is your new object", obj);
}
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