在序列中与hasMany关系工作，表不存在，为什么？

Question

在建立正确的关系，我如何建立这种关系以及我的情况下可能出现的问题方面需要您的帮助...

对我而言，sequelize的奇怪之处在于它会创建餐券，并给我错误，提示它不存在，我无法理解其背后的逻辑..

如何在这里设置我需要的关系？

const CustomerCoupon = sequelize.define('customer_coupon',{
  coupon_id:{
    type:Sequelize.BIGINT,
    allowNull:false
  },
  customer_id:{
    type:Sequelize.BIGINT,
    allowNull:false
  }
  },{
  schema:'couponsystem'
  });

const Customer = sequelize.define('customer',{
  customer_id:{
    type:Sequelize.BIGINT,
    primaryKey:true,
    allowNull:false
  },
  nickname: {
    type:Sequelize.STRING(100),
    allowNull:false,
    unique:true
  },
  firstname:{
    type:Sequelize.STRING(100),
    allowNull:false
  },
  lastname:{
    type:Sequelize.STRING(100),
    allowNull:false
  },
  email:{
    type:Sequelize.STRING(150),
    unique:true,
    allowNull:false
  },
  password:{
    type:Sequelize.STRING(150),
    unique:true,
    allowNull:false
  },
  country:{
    type:Sequelize.STRING(100),
    allowNull:false
  }
},{
  schema:'couponsystem',
  underscored:true
});

  const Coupon = sequelize.define('coupon',{
  coupon_id: {
    primaryKey:true,
    type:Sequelize.BIGINT,
    allowNull:false
  },
  title: {
    unique:true,
    type:Sequelize.STRING(50),
    allowNull:false
  },
  release_date: {
    type:Sequelize.DATE,
    release_time:Sequelize.DATE,
    allowNull:false 
  },
  expiration_date:{
    type:Sequelize.DATE,
    allowNull:false
  },
  price: {
    type:Sequelize.DOUBLE,
    allowNull:false
  },
  coupon_type:{
    type:Sequelize.ENUM('Traveling','Food','Camping','Restaurants'),
    allowNull:false
  }
},{
  schema:'couponsystem'
});

const User = sequelize.define('user', {
  user_id: {
    primaryKey:true,
    type:Sequelize.BIGINT,
    allowNull:false 
 },
  nickname: {
    type:Sequelize.STRING(150),
    unique:true,
    allowNull:false
  },
  email: {
    type:Sequelize.STRING(150),
    unique:true,
    allowNull:false
  },
  user_password: {
    type:Sequelize.STRING(150),
    unique:true,
    allowNull:false
  }
}, {
  schema:'couponsystem',
  underscored:true
});

    // CustomerCoupon.removeAttribute('id');
    Coupon.belongsToMany(Customer, {through: CustomerCoupon});
    Customer.belongsToMany(Coupon, {through: CustomerCoupon});

    User.hasOne(Customer,{foreignKey:'user_id'});

未处理的拒绝SequelizeDatabaseError：关系“ couponsystem.coupons”不存在

Answer 1

为此，Sequelize不接受单表名称，您必须使用称为freezeTableName的属性，以便它不会使优惠券成为优惠券

var Coupon = sequelize.define('coupon', { /* bla*/ }, {


  // disable the modification of tablenames; By default, sequelize will automatically
  // transform all passed model names (first parameter of define) into plural.
  // if you don't want that, set the following
  freezeTableName: true,

})