MySQL SUM 直到每年的特定日期

Question

我有一个customer_invoices包含的字段表invoiced_at的日期和total_price ，我需要的SUM total_price从每年直到同一天，今天，通过一年分组开始时的发票，并从一个特定的一年，我提供启动.

到目前为止我所做的：

public function totalIncomeToCurrentDayByYear($startingAt)
{
    return CustomerInvoice::selectRaw('sum(total_price) as total')
        ->where('customer_invoices.status', Status::VALIDATED)
        ->selectRaw("DATE_FORMAT(invoiced_at,'%Y') as year")
        ->whereRaw("DATE_FORMAT(invoiced_at,'%Y') >= $startingAt")
        ->groupBy('year')
        ->get()
        ->pluck('total', 'year');
}

我需要得到与此类似的结果：（在这种情况下，我得到了全年的总和，这不是我想要的）：

totalIncomeToCurrentDayByYear(2003); // ==> 

  #items: array:14 [▼
    2003 => "144.52"
    2006 => "11455.00"
    2007 => "27485.40"
    2008 => "39268.08"
    2009 => "37434.19"
    2010 => "443631.75"
    2011 => "2275159.26"
    2012 => "3874576.94"
    2013 => "4994901.19"
    2014 => "5968874.72"
    2015 => "7250182.95"
    2016 => "9017509.81"
    2017 => "10704557.00"
    2018 => "12637778.13"
  ]

例如，今天是January 23rd ，数组中的每一行都应该代表那一年直到January 23rd的total_price 。

Answer 1

试试下面的查询

CustomerInvoice::whereRaw("DATE_FORMAT(invoiced_at,'%Y') >= $startingAt")
   ->where('customer_invoices.status', Status::VALIDATED)
   ->whereRaw('MONTH(invoiced_at) < MONTH(NOW()) or 
    (MONTH(invoiced_at) = MONTH(NOW()) and DAY(invoiced_at) <= 
    DAT(NOW()))')
   ->select(DB::raw('YEAR(invoiced_at) invoiced_year' ),
    DB::raw('SUM(total_price) total_price'))-
    >groupBY(DB::raw('YEAR(invoiced_at)')
   ->orderBy(DB::raw('YEAR(invoiced_at)')->get();

Answer 2

放置另一个 where 过滤器，使发票日期小于当前日期。

public function totalIncomeToCurrentDayByYear($startingAt,$currentDate) { return CustomerInvoice::selectRaw('sum(total_price) as total') ->where('customer_invoices.status', Status::VALIDATED) ->selectRaw("DATE_FORMAT(invoiced_at,'%Y') as year") ->whereRaw("DATE_FORMAT(invoiced_at,'%Y') >= $startingAt")->whereRaw("invoiced_at <= $currentDate") ->groupBy('year') ->get() ->pluck('total', 'year'); }