[英]SQL: Get single result id from multiple rows
我有两个看起来像这样的表:
conversations
conversation_id | type | updated_at
50 | private | 2018-01-01 15:50:51
30 | group | 2019-01-01 15:50:49
100 | private | 2018-01-01 15:50:55
和
conversation_participants
user_id | conversation_id
1 | 100
3 | 50
5 | 99
6 | 50
6 | 30
3 | 30
2 | 30
我怎么能现在选择conversation_id
取决于两个user_id
和谈话的类型?
例如,给我来自用户 3 和 6 的conversation_id
,这是私有的。 所以我会得到conversation_id
50。
到目前为止我的方法:
SELECT *
FROM conversation_participants as cp
LEFT JOIN conversations as c
ON c.conversation_id = cp.conversation_id
WHERE c.type = 'private'
但是如何根据不同的行获取conversation_id
?
首先,您需要知道哪些转换是私密的
SELECT conversation_id
FROM conversations c
WHERE c.type = 'private'
然后您需要查看使用 SELF JOIN 的用户 3 和 6 的对话
SELECT conversation_id
FROM conversation_participants cp1
JOIN conversation_participants cp2
ON cp1.conversation_id = cp2.conversation_id
WHERE cp1 = 3
AND cp2 = 6
现在您只过滤私人对话
SELECT conversation_id
FROM conversation_participants cp1
JOIN conversation_participants cp2
ON cp1.conversation_id = cp2.conversation_id
WHERE conversation_id IN ( SELECT conversation_id
FROM conversations c
WHERE c.type = 'private' )
AND cp1 = 3
AND cp2 = 6
您还可以使用第三个连接
SELECT conversation_id
FROM conversation_participants cp1
JOIN conversation_participants cp2
ON cp1.conversation_id = cp2.conversation_id
JOIN conversations c
ON cp1.conversation_id = c.conversation_id
WHERE c.type = 'private'
AND cp1 = 3
AND cp2 = 6
我建议您首先根据参与者选择对话。 例如:
SELECT *
FROM conversation_participants cp
WHERE cp.user_id IN (3, 6)
要仅包含私人对话,您必须将conversation_participants
conversations
加入conversations
:
SELECT *
FROM conversation_participants cp
INNER JOIN conversations c ON
c.conversation_id = cp.conversation_id
WHERE
cp.user_id IN (3, 6)
AND c.type = 'private'
当然,此查询将为对话中的每个用户包含一行。 如果你只想有 1 行,你可以按对话分组。 像这样的东西:
SELECT
c.conversation_id,
c.updated_at,
COUNT(*) AS participant_count
FROM conversation_participants cp
INNER JOIN conversations c ON
c.conversation_id = cp.conversation_id
WHERE
cp.user_id IN (3, 6)
AND c.type = 'private'
GROUP BY
c.conversation_id,
c.updated_at
您需要使用GROUPING
子句,并添加一个HAVING
子句来优化您的查询(特别是如果您想搜索指定超过 2 个参与者的对话):
SELECT
c.conversation_id,
COUNT(*) AS participant_count
FROM conversations c
INNER JOIN conversation_participants cp ON
cp.conversation_id = c.conversation_id
WHERE
c.type = 'private'
AND cp.user_id IN (3, 6)
GROUP BY c.conversation_id
HAVING COUNT(*) = 2
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