[英]Getting selected radio button in JavaScript
在实际提出这个问题之前,我已经在这里尝试了很多解决方案,但是没有一个对我有用。
我试图使用onclick
处理程序,试图通过输入名称获取,尝试getElementId
,尝试elementClassName
我也试图循环它们var i = 0, length = radios.length; i < length; i++
var i = 0, length = radios.length; i < length; i++
var i = 0, length = radios.length; i < length; i++
没有为我工作!
这就是我的收音机的附加内容,使I made it short to be clean and easy to read
success:function(data) {
$('.shipoptions').empty();
$('.shipoptionstitle').empty();
$('.shipoptionstitle').append('<h6>Select your preferred method</h6>');
$.each(data.data, function(key, value) {
$.each(value.costs, function(key2, value2) {
$.each(value2.cost, function(key3, value3) {
// number format
var number = value3['value'];
var nf = new Intl.NumberFormat('en-US', {
maximumFractionDigits:0,
minimumFractionDigits:0
});
var formattedNumber = nf.format(number);
// number format
$('.shipoptions').append('<ul class="list-form-inline"><li><label class="radio"><input type="radio" name="postchoose" data-code="'+value['code']+'" data-service="'+value2['service']+'" value="'+ value3['value'] +'"><span class="outer"><span class="inner"></span></span>'+ value['code'] + ' - ' + value2['service'] + ' - Rp ' + nf.format(number) + ' - ' + value3['etd'] +'</label></li></ul>');
});
});
});
} //success function ends here
现在,我想获取
data-code
,data-service
和value
选定单选按钮value
对于临时人员,请帮助我在控制台中获取这些值,稍后我将自己修复打印部件。
任何想法?
<input type="radio" name="postchoose" data-code="'DC11'" data-service="'DS22'" value="'V33">
var dataCode = $('input[name="postchoose"]:checked').data('code');
var dataService = $('input[name="postchoose"]:checked').data('service');
var selectedVal= $("input:radio[name=postchoose]:checked").val();
$(function() {
$(".shipoptions").on('change', function(){
var radioValue = $("input[name='postchoose']:checked");
if(radioValue){
var val = radioValue.val();
var code = radioValue.data('code');
var service = radioValue.data('service');
alert("Your are a - " + code + "- " +service+ "- " +val);
}
});
});
我需要获得更高级别的单选按钮.shipoptions
试试这个jQuery方法。
$("input[type='radio']").click(function() {
var radioValue = $("input[name='postchoose']:checked").val();
var dataCode = $("input[name='postchoose']:checked").attr('data-code');
var dataService = $("input[name='gender']:checked").attr('data-service');
console.log(dataCode);
console.log(dataService);
console.log(radioValue);
});
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.