MySQL-返回相同订单ID的多行

Question

我正在尝试使用以下查询检索数据：

SELECT DISTINCT
o.id_order AS ID,
c.name AS ID_Carrier,
sl.name AS Store_Location,
o.date_add AS Order_date,
CASE WHEN h.id_order_state='2' THEN h.date_add END AS PAYMENT_VALIDATED,
CASE WHEN h.id_order_state='3' THEN h.date_add END AS IN_PROGRESS,
CASE WHEN h.id_order_state='160' THEN h.date_add END AS AWAITING,
CASE WHEN h.id_order_state='161' THEN h.date_add END AS SHIPPED,
CASE WHEN h.id_order_state='162' THEN h.date_add END AS READY_TO_COLLECT,
CASE WHEN h.id_order_state='84' THEN h.date_add END AS COLLECTED
FROM de_order_history h
LEFT JOIN de_orders o ON (o.id_order=h.id_order)
LEFT JOIN de_carrier c ON (o.id_carrier=c.id_carrier)
LEFT JOIN de_clickandcollect fs ON (o.id_order = fs.id_order)
LEFT JOIN de_store s ON (fs.id_store=s.id_store)
LEFT JOIN de_store_lang sl ON (sl.id_store=s.id_store)
WHERE sl.name = "XXX"
AND o.date_add >=  "2019-02-12 00:00:01"
AND o.date_add <=  "2019-02-12 23:59:59"

上面的查询返回的是有效数据，但我想将其转换为特定顺序的一行。 目前，我相信由于在同一id_order的de_order_history中创建了多个记录，

我在下面收到：

由于这些记录来自同一id_order，因此我想将其分成一行。

我尝试了以下方法：

MAX(CASE WHEN h.id_order_state='2' THEN h.date_add END) AS 01_PAYMENT_VALIDATED

不幸的是，由于“ END”，Prestashop 1.7返回错误。 我对此事也感到困惑。

有什么办法可以实现我的目标？

谢谢。

Answer 1

在请求group by尝试group by吗？

问候