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[英]how to select all records from one table and some from another table in cakephp 3.6
[英]How to select data from one table and get all associated records from another table?
我正在尽最大努力简化我的问题,希望我的解释将阐明其含义。
场景是这样的:
我有两个表,分别是: tbl_instructors
,它们具有讲师信息(例如讲师ID和名称), tbl_advisory
包含由特定讲师处理的所有班级记录,例如Course
, Year
和Section
。 所以我的桌子是这样的:
tbl_instructor:
id | name
----+--------------
001 | Jhon Doe
002 | Kaitlyn Moore
tbl_advisory:
instructor_id | course | year | section
---------------+---------------+-----------+-----------
001 | BSINT | 2nd Year | A
001 | BSINT | 2nd Year | C
001 | BSINT | 2nd Year | B
002 | BSBA | 1st Year | A
002 | BSBA | 1st Year | D
现在,我试图在我的PHP查询中使用INNER JOIN
选择教师ID和姓名及其相关的咨询信息:
<?php
$getAdvisory = "SELECT
ti.id AS id,
ti.name AS name,
ta.course AS ccourse,
ta.year AS cyear,
ta.section AS csection
FROM tbl_instructor as ti
INNER JOIN tbl_advisory as ta
ON ti.id = ta.instructor_id";
OpenConn()->query($getAdvisory);
if ($getAdvisory->num_rows > 0) {
while ($row = $getAdvisory->fetch_assoc()) {
$id = $row['id'];
$name = $row['name'];
}
?>
<td><?php echo $id; ?></td>
<td><?php echo $name; ?></td>
<td><button>View Advisory</button></td>
<?php
}
}
?>
这给了我在html / php表中的结果集:
id | name | action
-----+---------------+-----------
001 | John Doe | View Advisory
001 | John Doe | View Advisory
001 | John Doe | View Advisory
002 | Kaitlyn Moore | View Advisory
002 | Kaitlyn Moore | View Advisory
我的问题是我希望我的html表按教师ID进行区分,但仍返回每个教师的所有相关咨询信息,因为当我单击每个教师旁边的“ View Advisory
按钮时,我想显示该教师在模式中持有的课程。讲师姓名,以便在讲师删除或添加新咨询的情况下更新表。
我该如何实现? 提前致谢。
您需要DISTINCT子句
SELECT DISTINCT
ti.id AS id,
ti.name AS name,
ta.course AS ccourse,
ta.year AS cyear,
ta.section AS csection
FROM tbl_instructor as ti
INNER JOIN tbl_advisory as ta ON ti.id = ta.instructor_id
这样您应该获得
id | name | action
-----+---------------+-----------
001 | John Doe | View Advisory
002 | Kaitlyn Moore | View Advisory
如果值在不同的行上,则可以使用(伪)聚合函数
SELECT ti.id AS id,
ti.name AS name,
min(ta.course) AS ccourse,
min(ta.year) AS cyear,
min(ta.section) AS csection
FROM tbl_instructor as ti
INNER JOIN tbl_advisory as ta ON ti.id = ta.instructor_id
GROUP BY id, name
请检查此查询:
SELECT ti.*, GROUP_CONCAT( CONCAT( ta.course, ' ' , ta.year,' ', ta.section ) separator ' - ') as ColumnName
FROM tbl_instructor as ti
INNER JOIN tbl_advisory as ta ON ti.id = ta.instructor_id
GROUP BY ti.idid
输出:
| name | action
-----+---------------+-----------
001 | John Doe | BSINT 2nd Year a - BSINT 2nd Year b - BSINT 2nd Year c
002 | Kaitlyn Moore | BSBA 1st Year d - BSBA 1st Year a
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