在承诺解决之前表达 JS 退出 API

Question

在映射中，我有两个对象，它们将在switch进入default状态，1 个记录将进入ORDER_OPEN案例，并且该对象不会进入 if 语句，只会推送到orderArray但当 API 执行时，我只收到两个从default对象开始，当我记录orderArray它会在 API 执行后推入objectArray 。

router.get('/orderByPhone/:id', async (req, res) => {
const { ORDER_OPEN, ORDER_FILL, BITY_FILL, BITY_CANCEL, getOrderStatusValue } = require('../../lib/constants/orderStatus');
const statusUtils = require('../../lib/constants/orderStatus');
const apiUtils = require('../../lib/apiUtils');
const neo4jUtils = require('../../lib/neo4jUtils');
const orderArray = [];

try {
    const id = req.params.id;

    const response = await neo4jUtils.getOrders(1, id);

    response.records.map(async (record) => {
        switch (record._fields[0].properties.orderStatus) {

            case ORDER_OPEN:
                const ret = await apiUtils.fetchOrderStatus(record._fields[0].properties.bityId, record._fields[0].properties.token);

                if (ret.legacy_status == BITY_FILL) {
                    await neo4jUtils.updateOrderStatus(record._fields[0].properties.bityId, getOrderStatusValue(ret.legacy_status))
                } else if (ret.legacy_status == BITY_CANCEL) {
                    await neo4jUtils.updateOrderStatus(record._fields[0].properties.bityId, getOrderStatusValue(ret.legacy_status))
                }
                orderArray.push({
                    input: {
                        amount: ret.input.amount,
                        currency: ret.input.currency
                    },
                    ouput: {
                        amount: ret.output.amount,
                        currency: ret.output.currency
                    },
                    status: {
                        status: statusUtils.getOrderStatusValue(ret.legacy_status)
                    }
                });

                break;
            case ORDER_FILL:
                orderArray.push({
                    input: {
                        amount: record._fields[0].properties.fromAmount,
                        currency: record._fields[0].properties.fromCurrency
                    },
                    ouput: {
                        amount: record._fields[0].properties.toAmount,
                        currency: record._fields[0].properties.toCurrency
                    },
                    status: {
                        status: record._fields[0].properties.orderStatus
                    }
                });
                break;
            default:
                orderArray.push({
                    input: {
                        amount: record._fields[0].properties.fromAmount,
                        currency: record._fields[0].properties.fromCurrency
                    },
                    ouput: {
                        amount: record._fields[0].properties.toAmount,
                        currency: record._fields[0].properties.toCurrency
                    },
                    status: {
                        status: record._fields[0].properties.orderStatus
                    }
                });
                break;
        }
    });

} catch (error) {
    res.status(500).send(errorHandleing.FiveZeroZero)
}
res.status(200).json(orderArray);
 });

Answer 1

response.records.map(async (record) => {...}是一个同步函数，它将返回一个 promises 数组，您的代码不会wait {...}所有操作完成。这是您的主要原因请求只需要很少的时间来响应。

正确的方法，只需等到所有作业完成：

let promises = response.records.map(async (record) => {...}
await Promise.all(promises); // waiting....