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[英]how to collect data from json objects with multiple keys and push all values to single key:value array
[英]How to put all values into an array from a JSON object with specific key, Deep keys
我正在尝试解析一个包含大部分无用信息的大型 json 对象。 我正在尝试访问所有 '_text' 键及其值并将它们放入一个数组中。 前任:
const myObj = {
"_declaration": {
"_attributes": {
"version": "1.0",
"encoding": "UTF-8",
"standalone": "yes"
}
},
"w:document": {
"_attributes": {
"xmlns:wpc": "http://schemas.microsoft.com/office/word/2010/wordprocessingCanvas",
"xmlns:cx": "http://schemas.microsoft.com/office/drawing/2014/chartex",
"xmlns:cx1": "http://schemas.microsoft.com/office/drawing/2015/9/8/chartex",
"xmlns:cx2": "http://schemas.microsoft.com/office/drawing/2015/10/21/chartex",
"xmlns:cx3": "http://schemas.microsoft.com/office/drawing/2016/5/9/chartex",
"xmlns:cx4": "http://schemas.microsoft.com/office/drawing/2016/5/10/chartex",
"xmlns:cx5": "http://schemas.microsoft.com/office/drawing/2016/5/11/chartex",
"xmlns:cx6": "http://schemas.microsoft.com/office/drawing/2016/5/12/chartex",
"xmlns:cx7": "http://schemas.microsoft.com/office/drawing/2016/5/13/chartex",
"xmlns:cx8": "http://schemas.microsoft.com/office/drawing/2016/5/14/chartex",
"xmlns:mc": "http://schemas.openxmlformats.org/markup-compatibility/2006",
"xmlns:aink": "http://schemas.microsoft.com/office/drawing/2016/ink",
"xmlns:am3d": "http://schemas.microsoft.com/office/drawing/2017/model3d",
"xmlns:o": "urn:schemas-microsoft-com:office:office",
"xmlns:r": "http://schemas.openxmlformats.org/officeDocument/2006/relationships",
"xmlns:m": "http://schemas.openxmlformats.org/officeDocument/2006/math",
"xmlns:v": "urn:schemas-microsoft-com:vml",
"xmlns:wp14": "http://schemas.microsoft.com/office/word/2010/wordprocessingDrawing",
"xmlns:wp": "http://schemas.openxmlformats.org/drawingml/2006/wordprocessingDrawing",
"xmlns:w10": "urn:schemas-microsoft-com:office:word",
"xmlns:w": "http://schemas.openxmlformats.org/wordprocessingml/2006/main",
"xmlns:w14": "http://schemas.microsoft.com/office/word/2010/wordml",
"xmlns:w15": "http://schemas.microsoft.com/office/word/2012/wordml",
"xmlns:w16cid": "http://schemas.microsoft.com/office/word/2016/wordml/cid",
"xmlns:w16se": "http://schemas.microsoft.com/office/word/2015/wordml/symex",
"xmlns:wpg": "http://schemas.microsoft.com/office/word/2010/wordprocessingGroup",
"xmlns:wpi": "http://schemas.microsoft.com/office/word/2010/wordprocessingInk",
"xmlns:wne": "http://schemas.microsoft.com/office/word/2006/wordml",
"xmlns:wps": "http://schemas.microsoft.com/office/word/2010/wordprocessingShape",
"mc:Ignorable": "w14 w15 w16se w16cid wp14"
},
"w:body": {
"w:p": [
{
"_attributes": {
"w14:paraId": "53160B82",
"w14:textId": "77777777",
"w:rsidR": "00484DC0",
"w:rsidRDefault": "00484DC0",
"w:rsidP": "00264A78"
},
"w:pPr": {
"w:spacing": {
"_attributes": {
"w:after": "0",
"w:line": "240",
"w:lineRule": "auto"
}
},
"w:rPr": {
"w:sz": {
"_attributes": {
"w:val": "36"
}
},
"w:szCs": {
"_attributes": {
"w:val": "36"
}
}
}
}
},
{
"_attributes": {
"w14:paraId": "0FC460F5",
"w14:textId": "77777777",
"w:rsidR": "00880E84",
"w:rsidRDefault": "00880E84",
"w:rsidP": "00264A78"
},
"w:pPr": {
"w:spacing": {
"_attributes": {
"w:after": "0",
"w:line": "240",
"w:lineRule": "auto"
}
},
"w:rPr": {
"w:sz": {
"_attributes": {
"w:val": "36"
}
},
"w:szCs": {
"_attributes": {
"w:val": "36"
}
}
}
},
"w:r": {
"w:rPr": {
"w:sz": {
"_attributes": {
"w:val": "36"
}
},
"w:szCs": {
"_attributes": {
"w:val": "36"
}
}
},
"w:t": {
"_text": "Teaching Guide/Lesson Template"
}
}
}
...More of the object, this is the JSON format that I
then parse using JSON.parse in my code to read
const myArray = /*An array*/
//myArray should be ["Some text", "that I want", "in an array"]
顺序很重要 我用递归函数试过这个,但对象太大,我超过了最大调用堆栈。 是否有任何函数或库可以用于此功能?
使用Object.keys
一个递归函数,如下所示:
function getText(obj) { let text = []; Object.keys(obj).forEach(key => { if (key == "_text") { text.push(obj[key]); } if (typeof obj[key] == "object") { text.push(getText(obj[key])); } }); const flatten = function(arr, result = []) { for (let i = 0, length = arr.length; i < length; i++) { const value = arr[i]; if (Array.isArray(value)) { flatten(value, result); } else { result.push(value); } } return result; }; return flatten(text); } const myObj = { object1: { deeperLevel: { _text: "Some text" } }, object2: { _text: "that I want" }, object3: { deeperLevel: { EvenDeeper: { _text: "in an array" } } } }; const myArr = getText(myObj); console.log(myArr);
来自这个答案的扁平化算法。
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