[英]Php Array_filter to unset key values from array of arrays
我想从嵌套数组数组中取消设置数组元素。
我想执行递归数组过滤器,我不确定如何有效地做到这一点。
下面是原始数组。
[
[a] => 3
[b] => 0
[c] => [
[
[1] => aa
[2] => 1
[3] => [
[
[a1] => 6
[a2] => 5781
[a3] =>
[
[1] => 0
[2] => 19550
[3] => 5781
]
]
[
[a1] => 1
[a2] => 5781
[a3] =>[
[1] => 0
[2] => 19550
[3] => 5781
]
]
]
]
[
[1] => aa
[2] => 1
[3] => [
[
[a1] => 6
[a2] => 5781
[a3] =>
[
[1] => 0
[2] => 19550
[3] => 5781
]
]
[
[a1] => 1
[a2] => 5781
[a3] =>[
[1] => 0
[2] => 19550
[3] => 5781
]
]
]
]
]
]
预期数组
[
[a] => 3
[c] => [
[
[1] => aa
[3] => [
[
[a1] => 6
[a3] =>
[
[2] => 19550
[3] => 5781
]
]
[
[a1] => 1
[a3] =>[
[2] => 19550
[3] => 5781
]
]
]
]
[
[1] => aa
[3] => [
[
[a1] => 6
[a3] =>
[
[2] => 19550
[3] => 5781
]
]
[
[a1] => 1
[a3] =>[
[2] => 19550
[3] => 5781
]
]
]
]
]
]
如您所见,在每个嵌套数组的预期数组中,一些键值对已被删除。 我需要根据键名过滤数组。 那是我的键名是固定的,需要从里面的每个子数组中删除。
任何帮助将不胜感激。
这是一个基于递归foreach解决方案的示例,该解决方案使用您提供的数据集处理代码。
$sourceArray = array("a" => 3, "b" => 0, "c" => array("1" => "aa", "2" => 1, "3" => array("a1" => 6, "a2" => 5781, "a3" => array("1" => 0, "2" => 19550, "3" => 5781)), array( "a1" => 1, "a2" => 5781, "a3" =>array("1" => 0, "2" => 19550, "3" => 5781 ))), array( "1" => "aa", "2" => 1, "3" => array( array( "a1" => 6, "a2" => 5781, "a3" => array( "1" => 0, "2" => 19550,"3" => 5781))), array( "a1" => 1, "a2" => 5781, "a3" =>array( "1" => 0, "2" => 19550, "3" => 5781))));
print_r($sourceArray,1);
function removeKeys($keys, $sourceData) {
foreach ($sourceData as $key=>$val) {
if (in_array($key, $keys, true)) {
unset($sourceData[$key]);
} else if (is_array($val)) {
$sourceData[$key] = removeKeys($keys, $sourceData[$key]);
}
}
return $sourceData;
}
$keysToRemove = array("b","2","a2");
$newArray = removeKeys($keysToRemove, $sourceArray);
print_r($newArray);
尽管获取数据有点困难,但实现起来很简单。 我确实在此示例中注意到一个“错误”,因为如果键在原始数组中为“ 0”,即使它不在$ keys数组中,它仍然会被删除。
但是我假设此示例足以回答您的问题,并且不会发生我陈述的边缘情况(即,“ 0”不是数组中的键值。)如果您确实使用“ 0”作为键,可以添加其他逻辑来捕获这种情况,但这会使功能变慢一点,因此我将把选择权留给您。
(注意,上面提到的错误现在和代码中已修复。请参见下面的注释,以获取原始海报的解决方案)
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