[英]How can I modify my code to print a variable outside, that was initialized inside a try-catch?
这是我的代码,非常简单。 它应该获得10个双精度数,如果用户输入的不是双精度数,则捕获一个异常,然后从数字中取平均值:
import java.util.*;
public class QuestionOne {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
double i0, i1, i2, i3, i4,
i5, i6, i7, i8, i9;
System.out.println("Please enter a number for each input.");
try {
i0 = scan.nextDouble();
i1 = scan.nextDouble();
i2 = scan.nextDouble();
i3 = scan.nextDouble();
i4 = scan.nextDouble();
i5 = scan.nextDouble();
i6 = scan.nextDouble();
i7 = scan.nextDouble();
i8 = scan.nextDouble();
i9 = scan.nextDouble();
double isum = i0 + i1 + i2 + i3 + i4 + i5 + i6 + i7 + i8 + i9;
double iresult = isum / 10;
} catch (InputMismatchException e) {
System.out.println(e + "\nPlease, enter only numbers.");
}
System.out.println("The average of all the 10 numbers is " + isum);
}
}
因此,我正在尝试打印isum,但显然不能,因为它位于try-catch中。 漫长的一天后,我的大脑被炸得沸沸扬扬,当我准备安定下来时,意识到我有这项工作要做。 有谁知道我应该如何修改代码以能够取10双的平均值并打印出来?
不要尝试在try / catch之外打印出平均值; 最后在try块中打印它。 当发生异常时,您不想打印平均值。 用户输入了错误的内容,因此即使您可以打印出来,该计算也将无效。
try {
i0 = scan.nextDouble();
i1 = scan.nextDouble();
i2 = scan.nextDouble();
i3 = scan.nextDouble();
i4 = scan.nextDouble();
i5 = scan.nextDouble();
i6 = scan.nextDouble();
i7 = scan.nextDouble();
i8 = scan.nextDouble();
i9 = scan.nextDouble();
double isum = i0 + i1 + i2 + i3 + i4 + i5 + i6 + i7 + i8 + i9;
double iresult = isum / 10;
System.out.println("The average of all the 10 numbers is " + isum);
} catch (InputMismatchException e) {
System.out.println(e + "\nPlease, enter only numbers.");
}
如果有异常,将不会有任何结果,因此我将在try
块中进行打印。 另外,根据您的打印对帐单,您要打印结果(而不是总和)。
double iresult = isum / 10;
System.out.println("The average of all the 10 numbers is " + iresult);
} catch (InputMismatchException e) {
System.out.println(e + "\nPlease, enter only numbers.");
}
您需要在try块内移动平均打印,因为isum
变量只能在try
块内访问。 试试下面的代码
import java.util.*;
public class QuestionOne {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
double i0, i1, i2, i3, i4,
i5, i6, i7, i8, i9;
System.out.println("Please enter a number for each input.");
try {
i0 = scan.nextDouble();
i1 = scan.nextDouble();
i2 = scan.nextDouble();
i3 = scan.nextDouble();
i4 = scan.nextDouble();
i5 = scan.nextDouble();
i6 = scan.nextDouble();
i7 = scan.nextDouble();
i8 = scan.nextDouble();
i9 = scan.nextDouble();
double isum = i0 + i1 + i2 + i3 + i4 + i5 + i6 + i7 + i8 + i9;
double iresult = isum / 10;
System.out.println("The average of all the 10 numbers is " + isum);
} catch (InputMismatchException e) {
System.out.println(e + "\nPlease, enter only numbers.");
}
}
}
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