选择具有所有逗号分隔字符串的数据

Question

我有一个条件表

id   condition   member-id
 1    Fall         A1452
 2    Fall         A1453
 3    Dementia     A1452
 4    Dementia     A1453
 5    Fall         A1450
 6    Headaches    A1453

现在，我想要通过条件作为参数，例如“ Fall，Dementia”，我希望同时具有Fall和Dementia条件的那些会员ID

select * from conditions where condition IN('Fall,Dementia')

这将返回3条记录，但我需要同时拥有这两项的记录？

请记住，“秋季，痴呆症”是动态的，可能会更改为“秋季，痴呆症，头痛”

Answer 1

使用条件聚合

 select MemberId from 
 conditions
 where condition IN('Fall','Dementia')
 group by MemberId
 having count(distinct condition )=2 

Answer 2

 select distinct MemberId 
 from StackOverflow4
 where Condition in ('Fall','Dementia')
 group by memberId
 having count(MemberId)=2