[英]Accessing an object not working with a variable
这似乎很简单,但我撞墙了。 我的代码获取权重,访问对象数组以获取一个值,然后使用该值*权重来计算结果。 但是访问对象不适用于变量。
function calc(){
var gender;
if(document.getElementById("male").checked){
gender = "mensList";
} else if (document.getElementById("female").checked){
gender = "womensList";
} else {
alert("Please select a gender");
return false;
}
var kg = parseInt(document.getElementById("bwKg").value);
var grams = parseFloat(document.getElementById("bwGrams").value);
var bw = parseFloat(kg + grams);
var lifted = parseFloat(document.getElementById("liftWeight").value);
var theValue = womensList[bw]; // This works
var theValue = mensList[bw]; // This also works
var theValue = gender[bw]; // This doesn't work
var theValue = gender + "[\"" + bw + "\"]" // Nor this
var result = theValue * lifted;
document.getElementById("result").textContent = result;
}
var womensList = {
40.0: "1.4936",
40.1: "1.4915",
40.2: "1.4894",
40.3: "1.4872",
40.4: "1.4851",
// ......... etc
150.7: "0.7691",
150.8: "0.7691",
150.9: "0.7691"
};
var mensList = {
40.0: "1.3354",
40.1: "1.3311",
40.2: "1.3268",
40.3: "1.3225",
40.9: "1.2975",
// ......... etc
205.7: "0.5318",
205.8: "0.5318",
205.9: "0.5318"
};
这是你的问题:
if(document.getElementById("male").checked){
gender = "mensList"; //gender now contains a string only..
} else if
由于性别仅包含字符串,因此将无法使用:
var theValue = gender[bw]; // This doesn't work
您应该做的是:
if(document.getElementById("male").checked){
gender = mensList; //now gender contains an array provided mensList is defined beforehand ..
}
在您的代码中,您将gender
设置为string
不变。
if(document.getElementById("male").checked){
gender = "mensList";
} else if (document.getElementById("female").checked){
gender = "womensList";
}
应该
if(document.getElementById("male").checked){
gender = mensList;
} else if (document.getElementById("female").checked){
gender = womensList;
}
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