[英]Fibonacci function for user input numbers
我正在制作一个像斐波那契数列这样的程序,但是对于不超过用户提供的值的数字,例如:0 到 5 (0, 1, 2, 3, 4)。 程序需要计算数字的总和,向右移动并计算其他五个数字。 它适用于斐波那契数列,但不适用于更高的数字。 有谁知道如何做到这一点?
#include <stdio.h>
int main() {
int gg; //number which user inputs
int dg = 0; //first number
int next = 0;
int n;
int i;
printf("Number of series: ");
scanf("%d", &gg);
printf("Positive integer: ");//max number which outputs in printf("Series: \n", gg), etc. 1000;
scanf("%d", &n);
printf("Series: \n", gg); //result
for (i = 0; i < gg; i++) {
printf("%d, ", i);
}
next = gg + dg;
while(next <= n){
printf("%d, ", next);
dg = gg;
gg = next;
next = gg + dg;
}
return 0;
}
对于 0 到 5 的值,它应该输出:
0, 1, 2, 3, 4, 10, 20, 39, 76, 149, 294...
但它输出:
0, 1, 2, 3, 4, 5, 10, 15, 25, 40, 65, 105, 170, 275,
您需要保存最后的第 n 个值,而不仅仅是最后两个值。 在您的示例中,您需要存储最后五个值。 您可以为此使用数组:
#include <stdio.h>
#include <stdlib.h>
int main() {
int series_number;
int *previous_numbers;
int marker = 0;
int max_series_value;
int next = 0;
printf("Number of series: ");
scanf("%d", &series_number);
printf("Positive integer: ");
scanf("%d", &max_series_value);
printf("Series %d: \n", series_number);
previous_numbers = malloc(sizeof *previous_numbers *series_number);
for (int i = 0; i < series_number; i++) {
printf("%d, ", i);
previous_numbers[i] = i;
next += i;
}
previous_numbers[marker] = next;
marker = (marker+1) % series_number;
while(next <= max_series_value){
printf("%d, ", next);
next = 0;
for (int i = 0; i < series_number; i++) {
next += previous_numbers[(marker+i) % series_number];
}
previous_numbers[marker] = next;
marker = (marker+1) % series_number;
}
free(previous_numbers);
return 0;
}
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