来自xmltype / soap oracle的exctractvalue

Question

我需要从领域获得“无限的”价值

REQUEST_INFO:
...

<s:Envelope xmlns:env="http://schemas.xmlsoap.org/soap/envelope/" xmlns:s="http://schemas.xmlsoap.org/soap/envelope/">
<s:Header>
<X-dynaTrace xmlns="http://ns.dynatrace.com/wcf" xmlns:s="http://schemas.xmlsoap.org/soap/envelope/">FW3;-1003312095;1;-56375709;115092;0;975784079;78</X-dynaTrace>
</s:Header>
<s:Body xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<storeContract xmlns="xxx/integration">
<storeRequest>
<contract>
<contractSeries>ineedthis</contractSeries>

select extractvalue(XMLType(sap.REQUEST_INFO),'s/s/storeContract/storeRequest/contract/contractSeries')
from sap

无法获得价值

Answer 1

你试图提取路径

s/s/storeContract/storeRequest/contract/contractSeries

但是你的SOAP响应没有任何名为s节点; 它在命名空间 s有称为Envelope，Header和Body的节点。 所以你可能想要这条路径：

/s:Envelope/s:Body/storeContract/storeRequest/contract/contractSeries

它自己获取LPX-00601: Invalid token错误，因为它不知道s:是什么。 您可以使用第三个参数提供名称空间：

select extractvalue(XMLType(sap.request_info),
  '/s:Envelope/s:Body/storeContract/storeRequest/contract/contractSeries',
  'xmlns="xxx/integration" xmlns:s="http://schemas.xmlsoap.org/soap/envelope/"'
  ) as contractseries
from sap;

或者懒惰的方式是通配符命名空间，只识别你想要的最终节点：

select extractvalue(XMLType(sap.request_info),'//*:contractSeries') as contractseries
from sap;

但是不推荐使用extractvaue ，因此最好使用XMLQuery - 仍然是懒惰的：

select XMLQuery('//*:contractSeries/text()'
  passing XMLType(sap.request_info)
  returning content) as contractseries
from sap;

或使用显式名称空间：

select XMLQuery('
    declare default element namespace "xxx/integration";
    declare namespace s="http://schemas.xmlsoap.org/soap/envelope/";
    /s:Envelope/s:Body/storeContract/storeRequest/contract/contractSeries/text()'
  passing XMLType(sap.request_info)
  returning content) as contractseries
from sap;

CONTRACTSERIES                
------------------------------
ineedthis

分贝<>小提琴