展平一组对象和字符串

Question

我有一个像这样的对象数组：

const arr  = [  {
        realEstateBasicInfoResDto: {
            type: "Detached house",
            kind: "Class01"
        },
        assetId: "1",
        realEstateAddressInfoResDto: {
            county: null,
            municipality: null,
            municipalitySection: null,
            address: "Attica, N. Ionia, Iolkou",
            addrNumberFrom: 8,
            addrNumberTo: 0,
            addrLetterFrom: null,
            addrLetterTo: null,
            addressSec: null,
            addrSecLetterFrom: null,
            addrSecLetterTo: null,
            addrSecNumberFrom: 0,
            addrSecNumberTo: 0,
            postalCode: "1"
        },
        realEstateEstimationValuesResDtos: [ ]
    },

    {
        realEstateBasicInfoResDto: {
            type: "Detached house",
            kind: "Class01"
        },
        assetId: "11",
        realEstateAddressInfoResDto: {
            county: null,
            municipality: null,
            municipalitySection: null,
            address: "Attica, N. Ionia, Iolkou",
            addrNumberFrom: 8,
            addrNumberTo: 0,
            addrLetterFrom: null,
            addrLetterTo: null,
            addressSec: null,
            addrSecLetterFrom: null,
            addrSecLetterTo: null,
            addrSecNumberFrom: 0,
            addrSecNumberTo: 0,
            postalCode: "2"
        },
        realEstateEstimationValuesResDtos: [ ]
    },
]

我希望输出只有属性，里面没有对象键。
我正在使用这个功能：

const flatten = o =>
  Object.keys(o).reduce(
    (obj, key) =>
      typeof o[key] === "object" && o[key] !== null
        ? { ...obj, ...flatten(o[key]) }
        : { ...obj, [key]: o[key] },
    {}
  );

它似乎工作正常，但我在我的对象数组上得到的结果是这样的：

flatten(arr) = 
{
        addrLetterFrom: null
        addrLetterTo: null
        addrNumberFrom: 8
        addrNumberTo: 0
        addrSecLetterFrom: null
        addrSecLetterTo: null
        addrSecNumberFrom: 0
        addrSecNumberTo: 0
        address: "Attica, N. Ionia, Iolkou"
        addressSec: null
        assetId: "3"
        county: null
        kind: "Class01"
        municipality: null
        municipalitySection: null
        postalCode: null
        type: "Detached house"    
}

它实际上只返回最后一个展平的对象。 我想返回一个两个对象都展平的数组。 我错过了什么？ 谢谢。

Answer 1

您的flatten函数处理单个对象，因此您需要使用Array.map()迭代数组，并将您的 flatten 函数应用于每个对象：

 const arr = [{"realEstateBasicInfoResDto":{"type":"Detached house","kind":"Class01"},"assetId":"1","realEstateAddressInfoResDto":{"county":null,"municipality":null,"municipalitySection":null,"address":"Attica, N. Ionia, Iolkou","addrNumberFrom":8,"addrNumberTo":0,"addrLetterFrom":null,"addrLetterTo":null,"addressSec":null,"addrSecLetterFrom":null,"addrSecLetterTo":null,"addrSecNumberFrom":0,"addrSecNumberTo":0,"postalCode":"1"},"realEstateEstimationValuesResDtos":[]},{"realEstateBasicInfoResDto":{"type":"Detached house","kind":"Class01"},"assetId":"11","realEstateAddressInfoResDto":{"county":null,"municipality":null,"municipalitySection":null,"address":"Attica, N. Ionia, Iolkou","addrNumberFrom":8,"addrNumberTo":0,"addrLetterFrom":null,"addrLetterTo":null,"addressSec":null,"addrSecLetterFrom":null,"addrSecLetterTo":null,"addrSecNumberFrom":0,"addrSecNumberTo":0,"postalCode":"2"},"realEstateEstimationValuesResDtos":[]}]; const flatten = o => Object.keys(o).reduce( (obj, key) => typeof o[key] === "object" && o[key] !== null ? { ...obj, ...flatten(o[key]) } : { ...obj, [key]: o[key] }, {} ); const result = arr.map(flatten); console.log(result);