如何对嵌套数组中的每个项目使用lodash分组

Question

我有一个形式的json数组：

    [{
        "published": true,
        "tags": ["tag1", "tag2"],
        "categories": ["cat1"],
        "author": "some name",
        "post-format": "standard",
        "title": "Second Post,",
        "url-slug": "second-post",
        "first-published-on": "2019-03-28",
        "last-updated-on": "2019-03-28",
        "meta": {
            "title": "Second Post",
            "description": "Second post."
        },
        "excerpt": "Lorem ipsum dolor sit amet, consectetur adipiscing elit, sed do eiusmod tempor incididunt",
        "path": "2019/03/28/SecondPost.md"
    }, {
        "published": true,
        "tags": ["tag1", "tag2", "tag3"],
        "categories": ["cat1", "cat2"],
        "author": "some name",
        "post-format": "standard",
        "title": "Getting Started",
        "url-slug": "getting-started",
        "first-published-on": "2019-03-20",
        "last-updated-on": "2019-03-20",
        "meta": {
            "title": "Getting Started",
            "description": "Getting started post."
        },
        "excerpt": "Lorem ipsum dolor sit amet, consectetur adipiscing elit, sed do eiusmod tempor incididunt",
        "path": "2019/03/20/GettingStarted.md"
    }]

我想按标签将它们分组，格式如下：

[{
   "tag1": [{...}, {...}], 
   "tag2": [{...}, {...}], 
   "tag3": [{...}]
}]

我尝试使用lodash这样做：

const groupedByTag = _.groupBy(blogMetadata, function(postmetadata) {
        postmetadata.tags.map(tag => {
          return tag
        })
      })

显然，以上代码不正确，无法正常工作。 我看了一篇相关文章 ，但进展不大。 任何帮助表示赞赏。

Answer 1

您可以使用reduce和forEach

这里的主意是

• 首先，我们遍历obj变量的每个元素。
• 对于每个元素，我们遍历tags属性。
• 我们检查op已经具有该标签，然后我们推入该值，否则我们向具有相应值的op对象添加一个新键

 let obj = [{"published": true,"tags": ["tag1", "tag2"],"categories": ["cat1"],"author": "some name","post-format": "standard","title": "Second Post,","url-slug": "second-post","first-published-on": "2019-03-28","last-updated-on": "2019-03-28","meta": {"title": "Second Post","description": "Second post."},"excerpt": "Lorem ipsum dolor sit amet, consectetur adipiscing elit, sed do eiusmod tempor incididunt","path": "2019/03/28/SecondPost.md"}, {"published": true,"tags": ["tag1", "tag2", "tag3"],"categories": ["cat1", "cat2"],"author": "some name","post-format": "standard","title": "Getting Started","url-slug": "getting-started","first-published-on": "2019-03-20","last-updated-on": "2019-03-20","meta": {"title": "Getting Started","description": "Getting started post."},"excerpt": "Lorem ipsum dolor sit amet, consectetur adipiscing elit, sed do eiusmod tempor incididunt","path": "2019/03/20/GettingStarted.md"}] let final = obj.reduce((op,inp) => { inp.tags.forEach(e => { op[e] = op[e] || [] op[e].push(JSON.parse(JSON.stringify(inp))) }) return op },{}) console.log(final) 

Answer 2

您可以使用reduce ＆ forEach替代loadash 。 在reduce回调函数中，对tags进行迭代，并检查累加器对象是否存在该名称的key 。 如果存在，则推送当前对象，否则创建一个key并推送value

 let data = [{ "published": true, "tags": ["tag1", "tag2"], "categories": ["cat1"], "author": "some name", "post-format": "standard", "title": "Second Post,", "url-slug": "second-post", "first-published-on": "2019-03-28", "last-updated-on": "2019-03-28", "meta": { "title": "Second Post", "description": "Second post." }, "excerpt": "Lorem ipsum dolor sit amet, consectetur adipiscing elit, sed do eiusmod tempor incididunt", "path": "2019/03/28/SecondPost.md" }, { "published": true, "tags": ["tag1", "tag2", "tag3"], "categories": ["cat1", "cat2"], "author": "some name", "post-format": "standard", "title": "Getting Started", "url-slug": "getting-started", "first-published-on": "2019-03-20", "last-updated-on": "2019-03-20", "meta": { "title": "Getting Started", "description": "Getting started post." }, "excerpt": "Lorem ipsum dolor sit amet, consectetur adipiscing elit, sed do eiusmod tempor incididunt", "path": "2019/03/20/GettingStarted.md" }]; let newMapped = [data.reduce(function(acc, curr) { curr.tags.forEach(function(item) { if (acc[item]) { acc[item].push(curr) } else { acc[item] = [curr] } }) return acc; }, {})]; console.log(newMapped)