[英]how to find the difference between last two entries in Mysql
我需要一个关于 MySQL 中最后两个条目差异之间的差异的解决方案
SELECT DATE_FORMAT(order_datetime,'%m/%Y') as date,
SUM(order_total_after_tax) as number
FROM tbl_order
WHERE status = 'Confirmed'
GROUP BY DATE_FORMAT(order_datetime,'%Y/%m')
Limit 2
输出 :
date number
02/2019 2345.01
03/2019 103751.05
但我需要一个确切的解决方案是我需要找到最后两个结果之间的差异
2345.01 -103751.05
结果: -101406.04
在 MySQL 中如何做 Query 是什么?
你可以试试交叉连接
select a.date, a.number, b.number, a.number - b.number my_diff
from (
SELECT DATE_FORMAT(order_datetime,'%m/%Y') as date
, SUM(order_total_after_tax) as number
FROM tbl_order
where status='Confirmed'
GROUP BY DATE_FORMAT(order_datetime,'%Y/%m')
Limit 2
) a
CROSS JOIN (
SELECT DATE_FORMAT(order_datetime,'%m/%Y') as date
, SUM(order_total_after_tax) as number
FROM tbl_order
where status='Confirmed'
GROUP BY DATE_FORMAT(order_datetime,'%Y/%m')
) b ON a.date = b.date and a.number <> b.number
一种方法是cross join
,但它看起来像这样:
SELECT last.number - last_1.number
FROM (SELECT DATE_FORMAT(order_datetime,'%m/%Y') as date,
SUM(order_total_after_tax) as number
FROM tbl_order
WHERE status = 'Confirmed'
GROUP BY DATE_FORMAT(order_datetime,'%Y/%m')
ORDER BY date
LIMIT 1
) as last CROSS JOIN
(SELECT DATE_FORMAT(order_datetime,'%m/%Y') as date,
SUM(order_total_after_tax) as number
FROM tbl_order
WHERE status = 'Confirmed'
GROUP BY DATE_FORMAT(order_datetime,'%Y/%m')
ORDER BY date
LIMIT 1 OFFSET 1
) last_1
SELECT last.number - last_1.number FROM (SELECT DATE_FORMAT(order_datetime,'%m/%Y') as date, SUM(order_total_after_tax) as number FROM tbl_order WHERE status = 'Confirmed' GROUP BY DATE_FORMAT(order_datetime,'%Y/%m') ORDER BY date DESC LIMIT 1 ) as last CROSS JOIN (SELECT DATE_FORMAT(order_datetime,'%m/%Y') as date, SUM(order_total_after_tax) as number FROM tbl_order WHERE status = 'Confirmed' GROUP BY DATE_FORMAT(order_datetime,'%Y/%m') ORDER BY date DESC LIMIT 1 OFFSET 1 ) last_1
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.