将深层对象映射到新对象的更好方法

Question

这段代码用于将JSON转换为一个对象，其中每个名称对象都将变成其值的键，或者如果它具有自己的元素对象则将其分解并对其内容执行相同的操作。

有没有更好的方法来做到这一点，同时还能使JSON模式更具可扩展性？
有没有办法将所有内容简化为一个更简单的函数，即可以传递第一个元素并将其转换为架构所经过的任何深度？

const fs = require('fs');
{
    let scheme = JSON.parse('{"$schema":{"root":{"name":"THINGY","dtd":{"name":"DOCTYPE","value":"something.dtd","commentBefore":["?xml version='1.0'?","Version NULL"]},"ele":{"name":"REPORT","ele":[{"name":"SEGMENT0","ele":[{"name":"NUMBER1","value":""},{"name":"NUMBER2","value":""}]},{"name":"SEGMENT1","ele":[{"name":"RECORD1","ele":[{"name":"NUMBER1","value":""},{"name":"NUMBER2","value":""}]}]},{"name":"SEGMENT2","ele":[]},{"name":"SEGMENT3","ele":[]},{"name":"SEGMENT4","ele":[]},{"name":"SEGMENT5","ele":[]}]}}}}').$schema.root;
    let depth = 0;

    var compiled = {
        [scheme.ele.name]: scheme.ele.ele.map(function(i) {
            if (typeof i.ele != 'undefined') {
                return {
                    [i.name]: i.ele.map(function(k) {
                        if (typeof k.ele != 'undefined') {
                            return {
                                [k.name]: k.ele.map(function(p) {
                                    if (typeof p.ele != 'undefined') {
                                        return {
                                            [p.name]: p.ele
                                        };
                                    } else {
                                        return {
                                            [p.name]: p.value
                                        };
                                    }
                                })
                            };
                        } else {
                            return {
                                [k.name]: k.value
                            };
                        }
                    })
                };
            } else {
                return {
                    [i.name]: i.value
                };
            }
        })
    };
}

console.log(JSON.stringify(compiled, 0, 2));

我应该补充一点，这旨在最终还应用验证并在到达字符串对象时获取实际数据。

输出看起来像这样：

{
    "REPORT": [
    {
        "SEGMENT0": [
        {
            "NUMBER1": ""
        },
        {
            "NUMBER2": ""
        }
        ]
    },
    {
        "SEGMENT1": [
        {
            "RECORD1": [
            {
                "NUMBER1": ""
            },
            {
                "NUMBER2": ""
            }
            ]
        }
        ]
    },
    {
        "SEGMENT2": []
    },
    {
        "SEGMENT3": []
    },
    {
        "SEGMENT4": []
    },
    {
        "SEGMENT5": []
    }
    ]
}

Answer 1

您可以对对象进行解构，获取name ， ele和value并通过映射ele或value的对象返回以name为键的新对象和数组。

 const getData = ({ name, ele, value }) => ({ [name]: Array.isArray(ele) ? ele.map(getData) : value }); var scheme = JSON.parse('{"$schema":{"root":{"name":"THINGY","dtd":{"name":"DOCTYPE","value":"something.dtd","commentBefore":["?xml version=\\'1.0\\'?","Version NULL"]},"ele":{"name":"REPORT","ele":[{"name":"SEGMENT0","ele":[{"name":"NUMBER1","value":""},{"name":"NUMBER2","value":""}]},{"name":"SEGMENT1","ele":[{"name":"RECORD1","ele":[{"name":"NUMBER1","value":""},{"name":"NUMBER2","value":""}]}]},{"name":"SEGMENT2","ele":[]},{"name":"SEGMENT3","ele":[]},{"name":"SEGMENT4","ele":[]},{"name":"SEGMENT5","ele":[]}]}}}}').$schema.root, result = getData(scheme.ele); console.log(result); 

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Answer 2

Nina的答案更简洁，但这看起来更像您的代码，因此我认为我还是会发布它。

 let scheme = JSON.parse('{"$schema":{"root":{"name":"THINGY","dtd":{"name":"DOCTYPE","value":"something.dtd","commentBefore":["?xml version=\\'1.0 \\'?","Version NULL"]},"ele":{"name":"REPORT","ele":[{"name":"SEGMENT0","ele":[{"name":"NUMBER1","value":""},{"name":"NUMBER2","value":"1"}]},{"name":"SEGMENT1","ele":[{"name":"RECORD1","ele":[{"name":"NUMBER1","value":"2"},{"name":"NUMBER2","value":""}]}]},{"name":"SEGMENT2","ele":[]},{"name":"SEGMENT3","ele":[]},{"name":"SEGMENT4","ele":[]},{"name":"SEGMENT5","ele":[]}]}}}}').$schema.root; let newScheme = JSON.parse('{"$schema":{"root":{"name":"THINGY","dtd":{"name":"DOCTYPE","value":"something.dtd","commentBefore":["?xml version=\\'1.0 \\'?","Version NULL"]},"ele":{"name":"REPORT","ele":[{"name":"SEGMENT0","ele":[{"name":"NUMBER1","value":"1"},{"name":"NUMBER2","value":"3"}]},{"name":"SEGMENT1","ele":[{"name":"RECORD1","ele":[{"name":"NUMBER1","value":"4"},{"name":"NUMBER2","value":""}]}]},{"name":"SEGMENT2","ele":[]},{"name":"SEGMENT3","ele":[]},{"name":"SEGMENT4","ele":[]},{"name":"SEGMENT5","ele":[]}]}}}}').$schema.root; //Yay, recursion! function mapObj(a, o = {}) { let array = o[a.name] || []; for (let i = 0; i < a.ele.length; i++) { let b = a.ele[i]; array[i] = b.ele ? mapObj(b, array[i]) : { [b.name]: b.value }; } o[a.name] = array; return o; } let obj = mapObj(scheme.ele); console.log(obj); console.log(mapObj(newScheme.ele, obj));