繁体   English   中英

如何在另一个工作表上查找单元格值,并将值放在找到第一个值的行的另一列上

[英]How to find a cell value on another worksheet and place a value on another column for the row where the first value was found

(我承认我是vba的新手,所以如果这是一个愚蠢的问题我很抱歉 - 我也很抱歉任何英语错误)

一些背景:

我负责公司支持代理的活动时间表。 例如,他们的领导可以发送请求将其从计划中删除。 并且每个代理可以在同一天有多个请求。 (时间表是每天)

所以,我有两个电子表格,“请求”和“时间表”

在请求工作表上:我需要检查列的每种类型的请求(假期,休息日......)(“E”列)如果我发现此请求,我需要来自另一行的代理电子邮件(P列),在“计划”工作表(“A”列)上搜索此电子邮件,并在“AI”列上放置“1”(我必须报告每个请求的结果)

我一直有一个问题,主要是在“计划”工作表上找到代理并放置“1”,我已经尝试了其他代码,但这是我一直在努力的最后一个(工作同事已经过了使用“Do While”和“Find”)

(现在excel刚刚崩溃)

我尝试过的一些内容:

If wal.Cells(row, 5) = "Remove from the Schedule - Vacation" Then
    'Application.WorksheetFunction.Match(wal.Cells(row, 16).Value, wsc.Range("A:A"), 0).row
    wsc.Cells(Application.WorksheetFunction.Match(wal.Cells(row, 16).Value, wsc.Range("A:A"), 0).row, 35) = 1

ElseIf Cells(row, 5) = "Remove from the Schedule - Vacation" Then
    row = Application.WorksheetFunction.Match(wal.Cells(row, 16), sc.Range("A:A"), 0)
    wsc.Cells(row, 35) = 1

    Set wal = Worksheets("Alterações")
    Set wsc = Worksheets("Schedule")

    i = 5
    j = 41

    Do While wal.Range("E" & i) <> 0
        If wal.Range("E" & i) = "Remover do Schedule - Férias"  Then        
            Set agent = wal.Range("P" & i).Find(wsc.Range("A" & j).Value).row                
            Range("AI" & agent) = 1
        End If
    Loop

看看下面的Find示例

Sub demo()
    Dim wal As Worksheet: Set wal = Worksheets("Alterações")
    Dim wsc As Worksheet: Set wsc = Worksheets("Schedule")
    Dim rng As Range, UserRow As Range
    Dim UserEmail As String

    With wal
        Set rng = .Columns(5).Find("Remove from the Schedule - Vacation")
        If Not rng Is Nothing Then
            UserEmail = rng.Offset(0, 11).Value2
            Debug.Print rng.Address, UserEmail
            With wsc
                Set UserRow = .Columns(1).Find(what:=UserEmail)
                If Not UserRow Is Nothing Then
                    UserRow.Offset(0, Columns("AI").Column - UserRow.Column).Value2 = 1
                End If
            End With
        End If
    End With
End Sub

暂无
暂无

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM