在Javascript中从现有数组创建新数组

Question

我有数组：

const array_one = ["a", "b", "c"];

const array_two = ["d", "e"];

const array_Three = ["f", "g", "h"]

更多数组...

处理后返回结果：

[{"exp1":"a","exp2":"d","exp3":"f",},{"exp4":"a","exp5":"e","exp6":"g",},{"exp7":"a","exp8":"e","exp9":"h",},{"exp10":"b","exp11":"d","exp12":"f",}...,{"exp44":"c","exp45":"e","exp46":"h",}]

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我举了一个比我遇到的更简单的例子，我想补充一下。

const array = [{values: ["a, "b", "c"]}, {values: ["d, "e", "f"]}, {values: ["g, "h", "i"]}...];

数组中的对象数量是动态的，目前我需要检查一下有多少个对象的数组，并在条件下重复......，我觉得不好，和性能有关，我想寻找其他方法简化代码，更容易理解。

exp 代码： if(array.length === 1){loop array[0].values}

if(array.length === 2){loop array[0].values { loop array[1].values }}

if(array.length === 3){loop array[0].values { loop array[1].values { loop array[2].values } }}

对象数量不固定，所以检查是否有其他不便......

Answer 1

您只需要三个基本的嵌套循环，只需将值推送到新数组

 const array_one = ["a", "b", "c"]; const array_two = ["d", "e"]; const array_three = ["f", "g", "h"]; const final_array = [] let c = 0; for (let one of array_one) { for (let two of array_two) { for (let three of array_three) { final_array.push({[`exp${++c}`]:one, [`exp${++c}`]:two, [`exp${++c}`]:three}) } } } console.log(final_array)