您如何将这两个脚本合而为一？

Question

完全不熟悉Javascript。 如果可能，希望将这两个脚本合并为一个：

<script>
(function() {
var link = document.createElement('link');
link.rel = "stylesheet";
link.href = "https://www.example1.com";
document.querySelector("head").appendChild(link);
})();
</script>

<script>
(function() {
var link = document.createElement('link');
link.rel = "stylesheet";
link.href = "https://www.example2.com";
document.querySelector("head").appendChild(link);
})();
</script>

Answer 1

您的代码的类似脚本

<script>
(function(){
   var headUrl = ["https://www.example1.com","https://www.example2.com"];
   headUrl.forEach(function(linkURL) {
      let link = document.createElement('link');
      link.rel = "stylesheet";
      link.href = linkURL;
      document.querySelector("head").appendChild(link);
   })
})()
</script>

Answer 2

仅具有一个函数，并将变量作为参数传递。 您粘贴的两个函数基本上是相同的：

 <script>
    function oneFunction(href){
      var link = document.createElement('link');
      link.rel = "stylesheet";
      link.href = href;
      document.querySelector("head").appendChild(link);
    }
    oneFunction("https://www.example1.com");
    oneFunction("https://www.example2.com");
 </script>

Answer 3

<script>
(function() {
var link1 = document.createElement('link');
var link2 = document.createElement('link');
link1.rel = "stylesheet";
link1.href = "https://www.example1.com";
link2.rel = "stylesheet";
link2.href = "https://www.example2.com";
var head =  document.querySelector("head")
head.appendChild(link1);
head.appendChild(link2);

})();
</script>