如何在不更改原始数组的情况下破坏对象属性？

Question

试图从数组对象中删除类似属性，但无法重新声明抛出错误的作用域变量，我如何使用任何更好的方法从对象中删除类似属性，而无需更改原始数组？

main.js

const loggerResponse = transformedResponse.map(({ drugName, mailPrice,retailPrice, ...rest  }) => {
    const { copayEmployer, ...mailPriceRest } = mailPrice;
    const { copayEmployer, ...retailPriceRest } = retailPrice;
    return { ...rest, mailPrice: mailPriceRest , retailPrice: retailPriceRest};
  })

TransformationResponse

[
    {
        "isBrand": true,
        "drugName": "Lipitor",
        "drugStrength": "80 mg",
        "drugForm": "Tablet",
        "mailPrice": {
            "copayEmployer": 0,
            "prop2": "test"
        },
        "retialPrice": {
            "copayEmployer": 0,
            "prop2": "test"
        }

    }, {
        "isBrand": true,
        "drugName": "Metformin",
        "drugStrength": "500 mg",
        "drugForm": "Tablet",
        "mailPrice": {
            "copayEmployer": 50,
            "prop2": "test"
        },
        "retailPrice": {
            "copayEmployer": 0,
            "prop2": "test"
        }
    }

]

预期产量

[
    {
        "isBrand": true,
        "drugStrength": "80 mg",
        "drugForm": "Tablet",
        "mailPrice": {
            "prop2": "test"
        },
        "retialPrice": {
            "prop2": "test"
        }

    }, {
        "isBrand": true,
        "drugStrength": "500 mg",
        "drugForm": "Tablet",
        "mailPrice": {
            "prop2": "test"
        },
        "retailPrice": {
            "prop2": "test"
        }
    }

]

Answer 1

实际上，您的方法很棒，但是您需要进行一些更改，请尝试克隆对象而不是直接使用它，就像：

const loggerResponse = transformedResponse.map(({ drugName, mailPrice, retailPrice, ...rest  }) => {
  const { copayEmployer, ...mailPriceRest } = mailPrice || {};
  const { copayEmployer: copayEmployerRetail, ...retailPriceRest } = retailPrice || {};
  return { ...rest, mailPrice: { ...mailPriceRest, copayEmployer } , retailPrice: { ...retailPriceRest, copayEmployer: copayEmployerRetail }};
})

它应该可以解决问题。

Answer 2

这个解决方案怎么样？

const loggerResponse = function transform (originalArray) {
  originalArray.map( element => {
    delete element.drugName;
    delete element.mailPrice.copayEmployer;
    delete element.retialPrice.copayEmployer;
   });

  return originalArray;
}

const expectedArray = loggerResponse(transformedResponse);
console.log(expectedArray);

当然，如果需要，您可以克隆原始阵列。 并且请注意，仅使用slice() ，spread运算符等方法进行克隆将不会对其进行深入克隆，但是您可以使用以下代码来实现：

const deepClone = JSON.parse(JSON.stringify(transformedResponse));

然后，您可以在克隆的阵列上执行所有操作，而无需触摸原始阵列。