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[英]Add a custom item above logout item in Woocommerce my account menu
[英]How to add a linked item to another page in WooCommerce My Account menu
我正在尝试将链接项目添加到 WooCommerce 我的帐户菜单中的另一个页面(我的 BuddyPress 页面)。 是否可以?
我看到了这个帖子: How to add external custom url to woocommerce endpoint
但是,我在 BuddyPress 上的页面无法使用,因为它无法用 ULR 编写,也无法写入(可能只是我缺乏知识) :
add_filter ( 'woocommerce_account_menu_items', 'add_menu_item_to_tabbed_my_account' );
function add_menu_item_to_tabbed_my_account( $menu_links ){
// we will hook "anyuniquetext123" later
$new_item = array( 'anyuniquetext123' => __('Candidate Dashboard') );
// or in case you need 2 links
// $new_item = array( 'link1' => 'Link 1', 'link2' => 'Link 2' );
// array_slice() is good when you want to add an element between the other ones
$menu_links = array_slice( $menu_links, 0, 1, true )
+ $new_item
+ array_slice( $menu_links, 1, NULL, true );
return $menu_links;
}
add_filter( 'woocommerce_get_endpoint_url', 'custom_endpoint_url', 10, 4 );
function custom_endpoint_url( $url, $endpoint, $value, $permalink ){
if( $endpoint === 'anyuniquetext123' ) {
// BuddyPress My page link → <?php echo bp_loggedin_user_domain(); ?>
// I want to make a link of this
// ok, here is the place for your custom URL, it could be external
$url = **'http://alatta.org.ye/candidate-dashboard/';**
}
return $url;
}
其实,除了主要的问题,我改名字的时候,还被一个错误困扰。
[更改] '** 候选人仪表板 **' -> 'aaa'
[错误信息] 语法错误,意外的'' (T_STRING)
我用以下方法安全地解决了它:
add_filter ( 'woocommerce_account_menu_items', 'add_menu_item_to_tabbed_my_account' );
function add_menu_item_to_tabbed_my_account( $menu_links ){
$new_item = array( 'anyuniquetext123' => __('Candidate Dashboard') );
$menu_links = array_slice( $menu_links, 0, 1, true )
+ $new_item
+ array_slice( $menu_links, 1, NULL, true );
return $menu_links;
}
add_filter( 'woocommerce_get_endpoint_url', 'custom_endpoint_url', 10, 4 );
function custom_endpoint_url( $url, $endpoint, $value, $permalink ){
if( $endpoint === 'anyuniquetext123' ) {
// I only had to describe it normally
$url = bp_loggedin_user_domain();
}
return $url;
}
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